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Marrrta [24]
3 years ago
5

In most cases, letters of reconmendation are required for addmission to?

Physics
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

Get your recommenders to mention diverse achievements. ...

Help your recommenders with relevant info. ...

The letter should always include examples of things you did. ...

The letter should show how you improved over time. ...

The tone of the letter should not be too dry.

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PLZ help asap :-/<br>............................ ​
Misha Larkins [42]

Explanation:

<h2>[16]</h2>

\underline{\boxed{\large{\bf{Option \; A!! }}}}

Here,

  • \rm { R_1} = 2Ω
  • \rm { R_2} = 2Ω
  • \rm { R_3} = 2Ω
  • \rm { R_4} = 2Ω

We have to find the equivalent resistance of the circuit.

Here, \rm { R_1} and \rm { R_2} are connected in series, so their combined resistance will be given by,

\longrightarrow \rm { R_{(1,2)} = R_1 + R_2} \\

\longrightarrow \rm { R_{(1,2)} = (2 + 2) \; Omega} \\

\longrightarrow \rm { R_{(1,2)} = 4 \; Omega} \\

Now, the combined resistance of \rm { R_1} and \rm { R_2} is connected in parallel combination with \rm { R_3}, so their combined resistance will be given by,

\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \dfrac{1}{R_{(1,2)}} + \dfrac{1}{R_3} } \\

\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \Bigg ( \dfrac{1}{4} + \dfrac{1}{2} \Bigg ) \;\Omega} \\

\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \Bigg ( \dfrac{1 + 2}{4} \Bigg ) \;\Omega} \\

\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \Bigg ( \dfrac{3}{4} \Bigg ) \;\Omega} \\

Reciprocating both sides,

\longrightarrow \rm {R_{(1,2,3)}=  \dfrac{4}{3} \;\Omega} \\

Now, the combined resistance of \rm { R_1}, \rm { R_2} and \rm { R_3} is connected in series combination with \rm { R_4}. So, equivalent resistance will be given by,

\longrightarrow \rm {R_{(1,2,3,4)}=  R_{(1,2,3)} + R_4} \\

\longrightarrow \rm {R_{(1,2,3,4)}= \Bigg ( \dfrac{4}{3} + 2 \Bigg ) \; \Omega} \\

\longrightarrow \rm {R_{(1,2,3,4)}= \Bigg ( \dfrac{4 + 6}{3} \Bigg ) \; \Omega} \\

\longrightarrow \rm {R_{(1,2,3,4)}= \Bigg ( \dfrac{10}{3} \Bigg ) \; \Omega} \\

\longrightarrow \bf {R_{(1,2,3,4)}= 3.33 \; \Omega} \\

Henceforth, Option A is correct.

<h2>_________________________________</h2>

<h2>[17]</h2>

\underline{\boxed{\large{\bf{Option \; B!! }}}}

Here, we have to find the amount of flow of current in the circuit. By using ohm's law,

\longrightarrow V = IR

\longrightarrow 3 = I × 3.33

\longrightarrow 3 ÷ 3.33 = I

\longrightarrow 0.90 Ampere = I

Henceforth, Option B is correct.

<h2>____________________________</h2>

\tt \purple{Hope \; it \; helps \; you, Army! \heartsuit } \\

4 0
3 years ago
In a series circuit with three bulbs, adding another bulb will do what?
sergiy2304 [10]
Make all the bulbs dimmer by adding another bulb
6 0
3 years ago
Read 2 more answers
Why the object will not return to its original position?<br>why does the centre of mass fall?​
dusya [7]

Answer:

the object will not return to the original position because it will not have any forces helping it to go up the hill

the center of mass falls since it is going downwards

Hope this helps!! have a great day

Explanation:

8 0
4 years ago
Two straight wires are in parallel and carry electrical currents in opposite directions with the same magnitude of LaTeX: 2.02.0
koban [17]

Answer:

2.4\times 10^{-5} N

Explanation:

We are given that

I_1=I_2=2.0 A

Distance between the wires,d=5.0 mm=5\times 10^{-3} m

1mm=10^{-3} m

Length of other wire,l=0.3 m

Length of one wire is infinite.

We have to find the magnitude of force between the two wires.

We know that magnetic force

F=\frac{2\mu_0 I_1I_2 l}{4\pi d}

Where \frac{\mu_0}{4\pi}=10^{-7}

F=\frac{2\times 10^{-7}\times 2\times 2\times 0.3}{5\times 10^{-3}}

F=2.4\times 10^{-5} N

When the wires carrying equal current in opposite direction then the force between two wires repel to each other.

3 0
3 years ago
Friction between solids can be most accurately defined as the force that
ki77a [65]

Answer:

True

Explanation:

Friction between solids can be most accurately defined as the force that

opposes the sliding motion of two surfaces that are touching each other.

6 0
3 years ago
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