Question

Two parallel lines are crossed by a transversal. Horizontal and parallel lines y and z are cut by transversal x. At the intersection of lines y and x, the top right angle is (2 k + 11) degrees. At the intersection of lines z and x, the bottom left angle is 131 degrees. What is the value of k? k = 9 k = 20 k = 60 k = 71

Answer 1

Answer:

60

Step-by-step explanation:

Answer 2

Those two angles have the same measure, so you have

$2k+11=131 \iff 2k=120 \iff k=60$