Answer:
n △JKL, segment KL is the leg opposite ∠J and segment KL is the leg adjacent to ∠J.
Step-by-step explanation:
Given
See attachment for ![\triangle JKL](https://tex.z-dn.net/?f=%5Ctriangle%20JKL)
Required
Complete the blanks
From the question. we understand that
is the point of reference.
From the attached figure of ![\triangle JKL](https://tex.z-dn.net/?f=%5Ctriangle%20JKL)
Segment KL is opposite to ![\angle J](https://tex.z-dn.net/?f=%5Cangle%20J)
Segment JL is adjacent to ![\angle J](https://tex.z-dn.net/?f=%5Cangle%20J)
3 consecutive integers: a+2=b+1=c
a*b+2>3*c
substitute a and b definitions with c:
(c-2)*(c-1)+2>3c
c^2-c-2c+2+2>3c
c^2-3c+4>3c
c^2-6c+4>0
factoring
c^2-6c+4=(c-3)^2-5
(c-3)^2-5>0
(c-3)^2>5
c-3>sqrt(5)
c>sqrt(5)+3
c is an integer so we round up and don't have to calculate it exactly:
c=6, because they are consecutive a=4, b=5
4*5+2>3*6
20+2>18
The point (0,-5) is not located in the IV quadrant because your X is zero it will not cross into any quardant but rest on the opposite line (Y). Same for if Y were zero.
Answer:
Candace must make 32 sales.
Step-by-step explanation:
You can describe Candice weekly pay as a first degree function.
In our function, each sale n is the independent variable and her pay P is the the dependent variable. P is dependent of n, so we are going to write as P(n).
So, we can model the equation of P as a function of n by the following equation:
P(n) = 425 + 17.75n,
where, as the problem states, 425 is the flat rate and 17.75 is her comission for each sale n.
Now, the question is how many sales must Candace make to make $993 in one week. So, we want P(n) to be equals to $993 and we have to find n.
993 = 425 + 17.75n
Now we just need to solve this equation
993-425 = 17.75n
568 = 17.75n
n = 568/17.75
n = 32
So, to make $993 in one week, Candace must make 32 sales.