The slope of the line containing the points (6, 4) and (-5, 3) is: A. 1/11 B. 1 C. -1

Mathematics

2 answers:

Triss [41]3 years ago

6 0

Answer:

1/11

Step-by-step explanation:

svetoff [14.1K]3 years ago

5 0

$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-4}{-5-6}\implies \cfrac{-1}{-11}\implies \cfrac{1}{11}$

You might be interested in

Can any equation in point-slope form also be written in slope-intercept form?

Gekata [30.6K]

Answer:

Yes

Step-by-step explanation:

The way the equation is written in point-slope form is:

$y-y1=m(x-x1)$

The way we write an equation in slope-intercept form is:

$y=mx+b$

We can change point-slope form to slope-intercept form by first distributing the m and then adding y1 to both sides of the equation. When we do this we will get:

$y=mx-(m*x+y1)$ where $(m*x+y1) = b$