Answer:- The functions f(x) and g(x) are equivalent.
Explanation:-
Given functions:- 
and ![g(x)=\sqrt[3]{64^x }](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B64%5Ex%20%7D)
Simplify the functions by using law of exponents
Thus 
and ![g(x)=\sqrt[3]{64^x}=\sqrt[3]{(4^3)^x}= \sqrt[3]{4^{3x}}= \sqrt[3]{(4^x)^3}=4^x](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B64%5Ex%7D%3D%5Csqrt%5B3%5D%7B%284%5E3%29%5Ex%7D%3D%20%5Csqrt%5B3%5D%7B4%5E%7B3x%7D%7D%3D%20%5Csqrt%5B3%5D%7B%284%5Ex%29%5E3%7D%3D4%5Ex)
⇒f(x)=g(x)
Therefore ,the functions f(x) and g(x) are equivalent.
Answer:
false
Step-by-step explanation:
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
Its Not C or B, tried em and got em wrong
Step-by-step explanation:
