Ask question

Ask question

All categories

4 years ago

14

The number of square feet in the area of a square is 5 more than the number of feet in the perimeter of the square. Find the len

gth of a side.

1 answer:

nata0808 [166]4 years ago

6 0

Answer:5

Step-by-step explanation:The area of a 5x5 square is 25, and the perimeter would be 20. A 5x5 square's area is 5 more than the perimeter.

You might be interested in

Which shows another way to write 64?

Taya2010 [7]

None of those show another way to 64

6*6*6*6=1296

4*4*4*4*4*4=4096

6+6+6+6=24

6*4=24

Another way to show 64 is 8*8 or 4^3

4 0

4 years ago

There are 4 different magazines on Hannah's nightstand. Each

Lady_Fox [76]

Answer:

I need the answer did you get it

Step-by-step explanation:

6 0

3 years ago

Which graph represents the inequality y>3−x?

nekit [7.7K]

Answer:

B

Step-by-step explanation:

The first step is to draw the line y = 3 - x to see what the line itself looks like. Is it going from left to right as in A and C is going up as you go from right to left as in B and D? The graph on the left (below) gives you the answer. It is going up as you progress from right to left.

The next step is to answer which is it: B or D.

y has to be above the line. it is B. See the graph below on the right.

4 0

3 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

4 years ago

Ratio and Proportion can be used to convert weights between different systems of measurement. True False

sergeinik [125]

The answer you are looking for is true

7 0

3 years ago

Read 2 more answers