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olga nikolaevna [1]
3 years ago
15

Help Asap on both question!! will mark Brainliest!

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

Answer: Answer for 27 , It dropped 38 feet, (down) so -38 feet

Answer for 28, The difference between 4 and -7 is 11

Step-by-step explanation:

25 + 13 = 38 (but it was going down so its negative)

4 + 7 = 11

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In this question you are not allowed to use a calculator. Show all yo calculations. 6.1 Calculate: -24
Vera_Pavlovna [14]

if the -8-13 are both in the denominator

-24/(-8-13)

-24/-21

divide both sides by -3

[-24/-3] / [-21/-3]

8 / 7

if the -13 comes after the division

(-24/-8) -13

3 - 13

-10

7 0
2 years ago
7. 3х + 3 = 3(х + 1)
Alik [6]
X=0
Hopefully this helps
5 0
2 years ago
1.Find the dot product of the two given vectors, u=(1,6) and v=(-5,-2) 2. Find the dot product of v=-7i+4j and w=-6i+5j
Svet_ta [14]
The dot product of the two vectors will be given as follows:
v*w=(-7i+4j)*(-6i+5j)
=(-7*(-6))i+(4*5)j
=-42i+20j

Hence the answer is:
v*w=(-42i+20j)
8 0
3 years ago
Read 2 more answers
Otis plans to make 3 batches of sidewalk chalk How much plaster of paris does he need
den301095 [7]

Answer:

4\frac{1}{2} cups plaster of paris.

Step-by-step explanation:

Given:

for one batch of sidewalk chalk = 1\frac{1}{2} cup plaster of paris.

Number of bathes = 3

We need to find quantity of plaster of paris.

Solution:

For making 1 batch of sidewalk chalk = 1\frac{1}{2} cup plaster of paris.

For making 3 batches of sidewalk chalk = 3\times 1\frac{1}{2} cup plaster of paris.

= 3\times \frac{2\times 1+1}{2}

= 3\times \frac{2+1}{2}

= 3\times \frac{3}{2}

= \frac{3\times 3}{2}

= \frac{9}{2}

=4\frac{1}{2}

Therefore, he needed 4\frac{1}{2} cups plaster of paris.

5 0
3 years ago
IMPORTANT PLEASE!! 10 POINTS :)
s344n2d4d5 [400]

Answer:

The domain is all the possible inputs for this function. The range is all the possible outputs for this function.

The line starts at the <em>x-value</em> of 0 and ends at the <em>x-value</em> of 12. Therefore, your domain is D: [0, 12].

The line starts at the <em>y-value</em> of 9000 and ends at the <em>y-value</em> of 0. Therefore, your range is R: [0, 9000].

5 0
3 years ago
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