Answer:
<h2>
Therefore the length of a side of a cube is ![\sqrt[3]{64}\ or\ 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%5C%20or%5C%204)
</h2>
Step-by-step explanation:
The volume of a cube is expressed as L³ where L is the length of each side of the cube.
Given volume of a cube = 64in³
On substituting;
64 = L³
Taking the cube root of both sides to determine L we have;
![\sqrt[3]{64} = (\sqrt[3]{L})^{3}\\\sqrt[3]{64} = L\\L=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%20%28%5Csqrt%5B3%5D%7BL%7D%29%5E%7B3%7D%5C%5C%5Csqrt%5B3%5D%7B64%7D%20%3D%20L%5C%5CL%3D4)
Therefore the length of a side of a cube is
Answer:
57
Step-by-step explanation:
Straight line value=180
Given Value=123
Value of ∆TKL
=180-123
=57(Ans)
The <u>correct answer</u> is:
B) The variables are height and time. For the first part of the graph, the height is increasing slowly, which means the hiker is walking up a gentle slope. Flat parts of the graph show where the elevation does not change, which means the trail is flat here. The steep part at the end of the graph shows that the hiker is descending a steep incline.
Explanation:
The variables are marked on the graph. Time is marked along the x-axis, which means it is the independent variable. Height is marked along the y-axis, which means it is the dependent variable.
The first part of the graph rises slowly. This means the elevation does not change much over the time; this would be consistent with a gentle slope being climbed.
The flat areas are where the elevation does not change. This would be consistent with the hiker resting.
The steep decrease at the end shows that the elevation goes down quickly. This is consistent with the hiker climbing down a steep slope.
Correct me if im wrong but the answer is (B) hope this helps!
A=p(1+r/100)^n
A=2500(1+4/400)^16
A=2931.45
