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3 years ago

Of is directly proportional toy and x = 45 when

Mathematics

1 answer:

kompoz [17]3 years ago

4 0

Answer:

if x=ky, where k is constant.

value of x

45/3=k3/3

15=k, constant is 15

value of x when y =6

x=ky

x=15(6)

x=80

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In a sample of 41 temperature readings taken from the freezer of a restaurant, the mean is 29.7 degrees and the population stand

yKpoI14uk [10]

Answer: $=(29.1596\text{ degrees},\ 30.2404\text{ degrees})$

Step-by-step explanation:

Given: Sample size: n = 41

Sample mean $\overline{x}= 29.7$ degrees

Population standard deviation $\sigma=2.7$ degrees

Confidence level (c) = 80% =0.80

Significance level (a) = 1- c = 1-0.80 = 0.20

z-score for 80% confidence level : z = 1.2816 [from z-table]

Confidence level for population mean :-

$\overline{x}\pm z\dfrac{\sigma}{\sqrt{n}}$

$=29.7\pm ( 1.2816)\dfrac{2.7}{\sqrt{41}}$

$=29.7\pm ( 1.2816)\dfrac{2.7}{6.403124}$

$=29.7\pm ( 1.2816)(0.42167)$

$=29.7\pm 0.5404$

$=(29.7-0.5404,\ 29.7+0.5404)$

$=(29.1596,\ 30.2404)$

Hence, 80% confidence interval for the temperatures in the freezer $=(29.1596\text{ degrees},\ 30.2404\text{ degrees})$

7 0

3 years ago

Pls help I dont know how to do this

german

Answer:

1. CE = 63
2. x = 16

Step-by-step explanation:

Use proportions to solve.

Corresponding sides have same ratio.

<u>Question 1</u>

DE/EG = CE/EF

(6x + 3)/17 = (8x - 1)/21
21(6x + 3) = 17(8x - 1)
126x + 63 = 136x - 17
10x = 80
x = 8

CE = 8*8 - 1
CE = 63

<u>Question 2</u>

KM/MD = KZ/ZH

(x + 8)/21 = 32/28
x + 8 = 21*8/7
x + 8 = 24
x = 24 - 8
x = 16

5 0

3 years ago

There are 40 markers in a bag. Of the 10 scented markers, 6 are permanent markers. Half of the unscented markers are erasable.

Vera_Pavlovna [14]

Answer:

K12 ANSWER

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Assume the readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees

lozanna [386]

Answer: 0.0035

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

i.e. $\mu=0$ and $\sigma= 1$

Let x denotes the readings on thermometers.

Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_

$P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035$

Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035

The required region is attached below .

8 0

3 years ago

Help me with this please

kolbaska11 [484]

Answer:

Step-by-step explanation:

3 0

3 years ago