Answer:
I'm not smart sorry
Step-by-step explanation:
Hshshha good luck
Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Answer:
x = 125°
Step-by-step explanation:
The sum of the angles around a point = 360° , then
90 + 145 + x = 360°
235° + x = 360° ( subtract 235° from both sides )
x = 125°
Step-by-step explanation:
If they have the same shape, the red graph is a translation of the blue, which is given to be y=x^2.
Since the red graph stays on the y axis at two units above the blue (y=x^2) curve, therefore the red curve is given by y=x^2+2.
