Answer:
a. P(x = 0 | λ = 1.2) = 0.301
b. P(x ≥ 8 | λ = 1.2) = 0.000
c. P(x > 5 | λ = 1.2) = 0.002
Step-by-step explanation:
If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

a. What is the probability of selecting a carton and finding no defective pens?
This happens for k=0, so the probability is:

b. What is the probability of finding eight or more defective pens in a carton?
This can be calculated as one minus the probablity of having 7 or less defective pens.



c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?
We can calculate this as we did the previous question, but for k=5.

Answer:
[0.184, 0.266]
Step-by-step explanation:
Given:
Number of survey n =280
Number of veterans = 63
Confidence interval = 90%
Computation:
Probability of veterans = 63/280
Probability of veterans =0.225
a=0.1
Z(0.05) = 1.645 (from distribution table)
Confidence interval = 90%
So,
p ± Z*√[p(1-p)/n]
0.225 ± 1.645√(0.225(1-0.225)/280)
[0.184, 0.266]
Answer:
2/5
Step-by-step explanation:
The experimental probability is
P (heads) = number of heads/ total tosses
= 8/20
= 2/5

Plug in what we know:

Find the cube root of both sides:
![\sf~a=\sqrt[3]{2744}](https://tex.z-dn.net/?f=%5Csf~a%3D%5Csqrt%5B3%5D%7B2744%7D)
Simplify: