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dsp73
3 years ago
12

If the Moon orbit Earth twice as fast, but in the same orbit, the frequency of solar eclipses would:a. doubleb. be cut in halfc.

stay the same
Physics
1 answer:
slega [8]3 years ago
7 0

The definition of the Eclipse of the Sun says that it will form the formation of an eclipse of the sun when the moon and the sun are in exactly the same direction as seen from the earth. In such a way that the moon passes between the spectator in the earth and the sun.

We will start considering that both speed and orbit are independent factors, guarantors of the generation of an eclipse. The Moon's Orbit is inclined 5,145 ° with respect to the ecliptic plane. The existence of a solar eclipse occurs only when the moon passes through that ecliptic plane at the same time that it is closest to the sun. If you go through that plane twice, the sun will not be aligned to the 'first time', but it will be in the second time. Therefore the frequency of solar eclipses would remain the same as the frequency of alignment of the Moon, the sun and the earth will remain the same.

Therefore the correct answer is C.

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A 2.0 m × 4.0 m flat carpet acquires a uniformly distributed charge of −10 μC after you and your friends walk across it several
mamaluj [8]

Answer:

The  charge on the dust particle is  q_d  = 6.94 *10^{-13} \  C

Explanation:

From the question we are told that

    The length is  l = 2.0 \ m

    The width is  w = 4.0 \ m

   The charge is  q =  -10\mu C= -10*10^{-6} \ C

    The mass suspended in mid-air is m_a =  5.0 \mu g =  5.0 *10^{-6} \ g =  5.0 *10^{-9} \  kg

   

Generally the electric field on the carpet is mathematically represented as

           E =  \frac{q}{ 2 *  A  *  \epsilon _o}

Where \epsilon _o is the permittivity of free space with value \epsilon_o = 8.85*10^{-12}  \ \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

substituting values

           E =  \frac{-10*10^{-6}}{ 2 *  (2 * 4 )  *  8.85*10^{-12}}

           E = -70621.5 \  N/C

Generally the electric force keeping the dust particle on the air  equal to the force of gravity acting on the particles

        F__{E}} =  F__{G}}

=>     q_d *  E  =  m * g

=>      q_d  =  \frac{m * g}{E}

=>      q_d  =  \frac{5.0 *10^{-9} * 9.8}{70621.5}

=>     q_d  = 6.94 *10^{-13} \  C

4 0
3 years ago
if the displacement of a body is proportional to the square of time, state the nature of motion of the body ​
Liula [17]

Explanation:

If the displacement of an object is proportional to the square of the time taken then the body is moving with uniformly accelerated motion as it will follow Newton's second equation of motion for a particular initial velocity, which can be given by, s=ut+21at2.

hope this is helpful to you

3 0
3 years ago
One scientist is using an electromagnetic wave to map the dust between stars. The electromagnetic wave has shorter wavelength th
m_a_m_a [10]
Infrared light

it is also found under the name IR lights. although it’s technically invisible, it can still be seen with machinery up to at least 1050 nm in experiments.
3 0
3 years ago
Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of
Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

A=2\times10^{-6}m^2

* The young modulus of the steel is,

Y=2.1\times10^{11}\text{ Pa}

Solution:

The young modulus of the steel in terms of the force and extension is,

Y=\frac{F\times l}{A\times dl}

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

7 0
1 year ago
please help i really need this for a good grade!!!!! The Large Hadron Collider (LHC) in Europe is a large device that has spent
FrozenT [24]

Answer:

Humanity's "big science" experiments like the "Large Hadron Collider (LHC)" are by themselves not problems to be condemned. They show man's unending quests for answers: to discover their environment and its origin. Similar philosophical quests were summed up by St. Augustine, who noted that "our souls are restless until they find rest in GOD."  

Humanity will continue such experiments, the costs notwithstanding, until we come to faith in Yahweh, who is the creator of heaven and earth and in His Son.  When that faith is attained, our understanding will become complete.  We can then divert the billions to discover the future and not the past.

 

Explanation:

That scientists are spending billions of dollars on the "Large Hadron Collider (LHC) in Europe is a necessary evil.  Such billions of dollars are actually the required costs to acquire more knowledge about the created universe.  But, ordinary knowledge puffs.  It is only divine knowledge backed up by Faith in the Savior of the universe that is the antidote to prideful knowledge.

The earthsky.org says that "the most significant discovery to come from the LHC so far is the discovery of the Higgs boson (or the “God particle”) in 2012."  Nobel Prize-winning physicist Leon Lederman referred to the Higgs boson as the "God d..n Particle."  While he was intending to describe how difficult it was to detect the particle, he did not realize that he was 100% correct in the naming.  This discovered elementary particle (otherwise named the Higgs boson or the "God particle") proves that the particle force energy primarily originates from God.

Without God, there is no primary particle force energy which can give rise to the "big bang" theory.  God is that "invisible, universe-wide field that gave mass to all matter right after the Big Bang, forcing particles to coalesce into stars, planets, and everything else," according to Peter Higgs and Francois Englert (1964).  God also caused the Big Bang.

4 0
3 years ago
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