Answer:
A. 4,440 N
Explanation:
A Force applied on an object with mass 'm' can change its velocity in a unit time. This change is called acceleration.
If a force 'F' is applied on a body of mass 'm', it produces an acceleration 'a' in the body.
Force is give as :
F = ma
In our case,
m = 1200 kg a = 3.7 m/s²
F = 1200 x 3.7
F = 4440 kgm/s²
F = 4440 N
Answer:
Positive sign for negative velocity and minus sing for positive velocity
Explanation:
In the case of the negative velocity, the sign of the acceleration that reduces its magnitude is the positive sign, since being in the opposite direction to the movement indicates a deceleration or braking. In the case of the positive velocity, the sign of the acceleration that reduces its magnitude is the negative sign, since being in the opposite direction to the movement indicates a deceleration or braking. We observe that there will always be a reduction in the magnitude of the velocity if the acceleration goes in the opposite direction.
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just multiply each mouse's velocity components
then,
add them all up to get x,y total
There are missing data in the text of the problem (found them on internet):
- speed of the car at the top of the hill:
- radius of the hill:
Solution:
(a) The car is moving by circular motion. There are two forces acting on the car: the weight of the car
(downwards) and the normal force N exerted by the road (upwards). The resultant of these two forces is equal to the centripetal force,
, so we can write:
(1)
By rearranging the equation and substituting the numbers, we find N:
(b) The problem is exactly identical to step (a), but this time we have to use the mass of the driver instead of the mass of the car. Therefore, we find:
(c) To find the car speed at which the normal force is zero, we can just require N=0 in eq.(1). and the equation becomes:
from which we find
Answer:
Therefore the magnitude of tangential velocity is 20 m/s.
Explanation:
Tangential velocity:The tangential velocity is the straight line velocity of at any point of rotating object.
It is denoted by
ω= angular velocity
r = radius of rotating object.
Angular velocity: Angular velocity is ratio of angle to time.
Here ω= 50 rad/s and r = 0.4 m
Tangential velocity=(50 ×0.4)m/s
=20 m/s
Therefore the magnitude of tangential velocity is 20 m/s.