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ddd [48]
3 years ago
12

if the displacement of a body is proportional to the square of time, state the nature of motion of the body ​

Physics
1 answer:
Liula [17]3 years ago
3 0

Explanation:

If the displacement of an object is proportional to the square of the time taken then the body is moving with uniformly accelerated motion as it will follow Newton's second equation of motion for a particular initial velocity, which can be given by, s=ut+21at2.

hope this is helpful to you

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You push a table 8 meters for 16 minuutes and do 6720 j of work how much power do ypu use
Yuri [45]
P=W/t

P=Power
W=Work
t=Time

Convert 16 minutes in seconds:
16 mins = 960 secs

P=6720/960=7.23 W [Watt]
3 0
3 years ago
Whenever the forces applied to an object that is at rest are balanced, it will..l
lana [24]
Inertia is a force which keeps stationary objects at rest and moving objects in motion at ... False - Pounds is a unit of force commonly used in the British system of ... When a chemistry student places a beaker on a balance and determines it to be ... In this case, an object moving to the right could have a balance of forces if it is ...
5 0
3 years ago
A skateboarder flies horizontally off a cement planter. After 3 seconds the skateboarder lands on the ground with a final veloci
evablogger [386]

Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:

v = v_o + a \Delta t

A skateboarder flies horizontally off a cement planter. After a time of 3 seconds (Δt), he lands with a final velocity (v) of −4.5 m/s. Assuming the acceleration is -9.8 m/s² (a), we can calculate the initial velocity of the skateboarder (v₀) using the kinematic equation A.

v = v_o + a \Delta t\\\\v_o = v - a \Delta t = (-4.5 m/s) - (-9.8 m/s^{2} ) \times 3 s = 24.9 m/s

Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:

v = v_o + a \Delta t

Learn more: brainly.com/question/4434106

3 0
3 years ago
What is an unbalanced force
Butoxors [25]
There's no such thing as "an unbalanced force".

If all of the forces acting on an object all add up to zero, then we say that
<span>the group </span>of forces is balanced.  When that happens, the group of forces
has the same effect on the object as if there were no forces on it at all. 

An example: 
Two people with exactly equal strength are having a tug-of-war.  They pull
with equal force in opposite directions.  Each person is sweating and straining,
grunting and groaning, and exerting tremendous force.  But their forces add up
to zero, and the rope goes nowhere.  The <u>group</u> of forces on the rope is balanced.

On the other hand, if one of the offensive linemen is pulling on one end of
the rope, and one of the cheerleaders is pulling on the other end, then their
forces don't add up to zero, because even though they're opposite, they're
not equal.  The <u>group</u> of forces is <u>unbalanced</u>, and the rope moves.

A group of forces is either balanced or unbalanced.  A single force isn't.
7 0
3 years ago
1)the car's engine power is 44000W. Explain this number in a physical sense
Ratling [72]

Answer:

1) It expresses the rate (top speed) at which it can move with time.

2) P = 20 W

3) h = 18 km

Explanation:

1) Power is the rate of transfer of energy.

⇒ Power = \frac{Energy(or workdone)}{Time}

i.e P = \frac{E}{t}

Thus a car's engine power is 44000W implies that the engine of the car can propel the car at this rate. This expresses the rate (top speed) at which it can move with time.

2) m = 400g = 0.4 kg

    t = 20 s

h = 100m

g = 10 m/s^{2}

P = \frac{mgh}{t}

  = \frac{0.4*10*100}{20}

  = \frac{400}{20}

P = 20 W

3) u = 600 m/s

   g = 10 m/s^{2}

From the third equation of free fall,

V^{2} = U^{2} - 2gh

V is the final velocity, U is the initial velocity, h is the height.

0 = (600)^{2} - 2 x 10 x h

0 = 360000 - 20h

20h = 360000

h = \frac{360000}{20}

  = 18000

h = 18 km

The maximum height of the bullet would be 18 km.

3 0
3 years ago
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