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shutvik [7]
3 years ago
5

Un objeto con una carga de 7μC se coloca en un campo eléctrico uniforme de 200N/C con dirección vertical. ¿Cuál es el valor de l

a masa del objeto si se queda "flotando" en el campo?
Physics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

 m = 1,429 10⁻⁴ kg

Explanation:

For the object to remain floating, the translational equilibrium condition must be met, we set a reference system where the vertical upward direction is positive

          F_e -W = 0

          F_e = W

          q E = m g

we clear

         m = \frac{qE}{g}

let's calculate

        m = \frac{7 \ 10^{-6}  \ 200}{ 7 }

        m = 1,429 10⁻⁴ kg

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Two friends of different masses are on the playground. They are playing on the seesaw and are able to balance it even though the
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Answer:

They are able to balance torques due to gravity.

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Two long parallel wires carry currents of 20 a and 5.0 a in opposite directions. the wires are separated by 0.20 m. what is the
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The two wires carry current in opposite directions: this means that if we see them from above, the magnetic field generated by one wire is clock-wise, while the magnetic field generated by the other wire is anti-clockwise. Therefore, if we take a point midway between the two wires, the resultant magnetic field at this point is just the sum of the two magnetic fields, since they act in the same direction.

Therefore, we should calculate the magnetic field generated by each wire and then calculate their sum. We are located at a distance r=0.10 m from each wire. 

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B=B_1 + B_2 = 4 \cdot 10^{-5} T + 1 \cdot 10^{-5}T=5 \cdot 10^{-5} T
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