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shutvik [7]
3 years ago
5

Un objeto con una carga de 7μC se coloca en un campo eléctrico uniforme de 200N/C con dirección vertical. ¿Cuál es el valor de l

a masa del objeto si se queda "flotando" en el campo?
Physics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

 m = 1,429 10⁻⁴ kg

Explanation:

For the object to remain floating, the translational equilibrium condition must be met, we set a reference system where the vertical upward direction is positive

          F_e -W = 0

          F_e = W

          q E = m g

we clear

         m = \frac{qE}{g}

let's calculate

        m = \frac{7 \ 10^{-6}  \ 200}{ 7 }

        m = 1,429 10⁻⁴ kg

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∆U = - ∫-Fdx

=  ∫F.dx

Since F = 40x - 6x² and x moves from x = 0 to x = 2 m, we integrate thus, ∆U =  ∫₀²F.dx

=  ∫₀²(40x - 6x²).dx

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=  ∫₀²(40x²/2 - 6x³/3)

=  ∫₀²(20x² - 2x³)

= [20x² - 2x³]₀²

= [(20(2)² - 2(2)³) - (20(0)² - 2(0)³)

= [(20(4) - 2(8)) - (0 - 0))

= [80 - 16 - 0]

= 64 J

5 0
3 years ago
2500000000000 in scientific notation
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Your answer is 2.5 x 10^(11).

Please take the time to rate and thank me if you feel I helped you! Thanks, it means a lot to me. :)
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