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Rzqust [24]
3 years ago
11

A motorcycle is capable of accelerating at 4.7 m/s^2, starting from rest, how far can it travel in 3 seconds?

Physics
2 answers:
tankabanditka [31]3 years ago
7 0
21.15m should be the answer ^_^
maw [93]3 years ago
5 0

Answer: 21.15m

Explanation:

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What equation describes conservation of charge?
Phantasy [73]

Answer:

The equation which describes conservation of charge is Q_{initial} - Q_{final } = 0

Explanation:

The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.

let the sum of initial charges = Q_{initial}

let the sum of the final charges = Q_{final}

Q_{initial } = Q_{final}\\\\Q_{initial } - Q_{final} = 0

Therefore, the equation which describes conservation of charge is Q_{initial} - Q_{final } = 0

6 0
3 years ago
What is an interaction pair?
Alchen [17]
A set of two forces that are in opposite directions, have equal magnitudes and act on different objects
6 0
3 years ago
A ball is thrown downward at 12 m/s from a windowsill 35 m above the ground. At the same time, another ball is thrown upward at
wariber [46]

Answer:

The second ball lands 1.5 s after the first ball.

Explanation:

Given;

initial velocity of the ball, u = 12 m/s

height of fall, h = 35 m

initial velocity of the second, v = 12 m/s

Time taken for the first ball to land;

t = \sqrt{\frac{2h}{g} }\\\\t =\sqrt{ \frac{2*35}{9.8}}\\\\t = 2.67 \ s

determine the maximum height reached by the second ball;

v² = u² -2gh

at maximum height, the final velocity, v = 0

0 = 12² - (2 x 9.8)h

19.6h = 144

h = 144 / 19.6

h = 7.35 m

time to reach this height;

t_1 = \sqrt{\frac{2h}{g} }\\\\t_1 =  \sqrt{\frac{2*7.35}{9.8}}\\\\t_1 = 1.23 \ s

Total height above the ground to be traveled by the second ball is given as;

= 7.35 m + 35m

= 42.35 m

Time taken for the second ball to fall from this height;

t_2 = \sqrt{\frac{2h}{g} }\\\\t_2 = \sqrt{\frac{2*42.35}{9.8} }\\\\t_2 = 2.94 \ s

total time spent in air by the second ball;

T = t₁ + t₂

T = 1.23 s + 2.94 s

T = 4.17 s

Time taken for the second ball to land after the first ball is given by;

t = 4.17 s -  2.67 s

T = 1.5 s

Therefore, the second ball lands 1.5 s after the first ball.

4 0
2 years ago
What would a scientist most likely do to demonstrate the effects of a tsunami? (2 points) construct tsunami models make underwat
Otrada [13]
Construct tsunami models
5 0
3 years ago
The pressure in a water line is 1500 kpa. what is the line pressure in (a) lb/ft2 units and (b) lbf/in2 (psi) units?
kotegsom [21]

To solve this problem, we know that:

1 psi = 6894.76 Pa

1 lb / ft^2 = 47.88 Pa

 

Therefore:

a. 1500 x 10^3 Pa * (1 lb / ft^2 / 47.88 Pa) = 31,328.32 lb / ft^2

 

b. 1500 x 10^3 Pa * (1 psi / 6894.76 Pa) = 217.56 psi

7 0
3 years ago
Read 2 more answers
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