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Rzqust [24]
3 years ago
11

A motorcycle is capable of accelerating at 4.7 m/s^2, starting from rest, how far can it travel in 3 seconds?

Physics
2 answers:
tankabanditka [31]3 years ago
7 0
21.15m should be the answer ^_^
maw [93]3 years ago
5 0

Answer: 21.15m

Explanation:

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2 years ago
What is the magnitude of the acceleration vector which causes a particle to move from velocity −5i−2j m/s to −6i+ 7j m/s in 8 se
shusha [124]

Answer:

Acceleration, a=\dfrac{1}{8}(-i+9j)\ m/s^2

Explanation:

Initial velocity of a particle in vector form, u = (-5i - 2j) m/s

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Time taken, t = 8 seconds

We need to find the magnitude of acceleration vector. The changing of velocity w.r.t time is called acceleration of a particle. It is given by :

a=\dfrac{v-u}{t}

a=\dfrac{(-6i+7j)\ m/s-(-5i-2j)\ m/s}{8\ s}    

a=\dfrac{(-i+9j)}{8\ s}\ m/s^2    

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a=\dfrac{1}{8}(-i+9j)\ m/s^2

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