Question

Write a program that first gets a list of integers from input. Then, get another value from the input, and output all integers less than or equal to that value. If the input is 5 50 60 140 200 75 100, the output is: 50 60 75.

Answer 1

Answer:

The c++ program for the given scenario is given below.

#include <iostream>

using namespace std;

int main() {

   int len=20, arr[len], data;    

   // initialize all elements of the array to 0

   for(int i=0; i<len; i++)

   {

       arr[i] = 0;

   }    

   cout<<"This program outputs all the numbers less than or equal to the given number."<<endl;

   cout<<"Enter the list of numbers. Enter 0 to stop entering the numbers. "<<endl;

   for(int i=0; i<len; i++)

   {

       cin>>arr[i];        

       // 0 indicates user wishes to stop entering values  

       if(arr[i] == 0)

           break;

       else

           continue;

   }    

   // number from which the list is to be compared

   cout<<"Enter the number to be compared."<<endl;

   cin>>data;

     

   cout<<"The values less than or equal to the number "<<data<<" are "<<endl;

   for(int i=0; i<len; i++)

   {  

       // 0 indicates the end of the list entered by the user

       if(arr[i]==0)

           break;

       if(arr[i] <= data)

           cout<<arr[i]<<endl;

   }    

   return 0;    

}  

OUTPUT

This program outputs all the numbers less than or equal to the given number.

Enter the list of numbers. Enter 0 to stop entering the numbers.  

23

45

67

89

10

0

Enter the number to be compared.

59

The values less than or equal to the number 59 are  

23

45

10

Explanation:

This program takes input only from the user and makes no assumptions.

The list of numbers entered by the user are stored in an array. If the user input is less than the size of the array, the remaining elements are set to 0.

While taking input from the user, if any element of the array is found to be 0, the loop is discontinued.

for(int i=0; i<len; i++)

   {

       cin>>arr[i];        

       if(arr[i] == 0)

           break;

       else

           continue;

   }  

Same test is applied when all the numbers less than the given number are displayed.

for(int i=0; i<len; i++)

   {  

        if(arr[i]==0)

           break;

       if(arr[i] <= data)

           cout<<arr[i]<<endl;

   }

The above program takes into account all the specifications in the given question.