1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
m_a_m_a [10]
3 years ago
15

The two principal catalysts for the Information Age have been:________.

Computers and Technology
1 answer:
jok3333 [9.3K]3 years ago
6 0

Answer:

The two principal catalysts for the Information Age have been computers and communication networks.

Explanation:

Since the invention of computers and internet, people can get the information they need faster than ever before due to the ease of use of both technologies and the relatively cheap price of acquiring the technology.

You might be interested in
(The Location class) Design a class named Location for locating a maximal value and its location in a two-dimensional array. The
-Dominant- [34]

Answer:

Here is the Location class:

public class Location {   //class name

   public int row;  // public data field to hold the value of no. of rows

   public int column;  // public data field to hold the value of no. of columns

   public double maxValue;   //public data field to hold the maximum value

   public Location(int row, int column, double maxValue) { //parameterized constructor of Location class

//this keyword is used to refer to a current instance variable and used to avoid naming conflicts between attributes and parameters with the same name

       this.row = row;  

       this.column = column;  

       this.maxValue = maxValue;     }  

   public static Location locateLargest(double[][] a) {   //method that takes a 2 dimensional array a as argument and returns the location of the largest element

       int row = 0;  //initializes row to 0

       int column = 0;  //initializes column to 0

       double maxValue = a[row][column];   //stores largest element

       for (int i = 0; i < a.length; i++) {  //iterates through rows of a[] array

           for (int j = 0; j < a[i].length; j++) {  //iterates through columns of array

               if (maxValue < a[i][j]) {  //if the maxValue is less than the element of 2 dimensional array at ith row and jth column

                   maxValue = a[i][j];  //then set that element to maxValue

                   row = i;  // i is set to traverse through rows

                   column = j;   }             }         }  // i is set to move through columns

       return new Location(row,column,maxValue);     }  } //calls constructor of class by passing row, column and maxValue as argument

Explanation:

Here is the Main class with a main() function to  test program  

import java.util.Scanner;   //to accept input from user

public class Main {   //class name

   public static void main(String[] args) {   //start of main function

       Scanner scan = new Scanner(System.in);  //creates Scanner class object to scan the input from user

 System.out.print("Enter the number of rows and columns in the array: ");  //prompt for user

       int row = scan.nextInt();  // reads value of row from user

       int column = scan.nextInt();  //reads input value of column

       double[][] array = new double[row][column];   //declares a 2 dimensional array named array

       System.out.println("Enter the array:");  //prompts to enter array elements

       for (int i = 0; i < array.length; i++) {  //iterates through the rows of array until the size of array is reaced

           for (int j = 0; j < array[i].length; j++) {  //iterates through the columns of array

               array[i][j] = scan.nextDouble();    }    }   //reads each element at i-th row and j-th column

       Location location = Location.locateLargest(array);  //calls locateLargest method by passing array to it in order to locate the largest element in the array

System.out.println("The largest element in a two-dimensional array is: " + location.maxValue);  //displays the largest element of array

       System.out.println("The location of the largest element is at (" + location.row + ", " + location.column + ")");       }    } //displays the location of the largest element in the two dimensional array

Suppose the user enters 2 rows and 2 columns. The elements are:

1         5.5

4.5      3

The program works as follows:

for (int i = 0; i < array.length; i++) this outer loop iterates through rows

i = 0

inner loop for (int j = 0; j < array[i].length; j++) iterates through columns

array[i][j] = scan.nextDouble(); reads the element at position i-th row and j-th column. This becomes:

array[0][0] = scan.nextDouble();

so element at 0th row and 0th column is 1

Location location = Location.locateLargest(array); now this calls the method which works as follows:

double maxValue = a[row][column]; this becomes:

double maxValue = a[0][0];

so maxValue = 1

for (int i = 0; i < a.length; i++) this loop in method iterates through rows and  for (int j = 0; j < a[i].length; j++) this iterates through columns of array

if (maxValue < a[i][j]) this becomes:

if (maxValue < a[0][0])

As we know that maxValue = 1 so this if condition is true.

                   maxValue = a[i][j];  this becomes:

             maxValue = a[0][0];  

maxValue = 1

Now set row = 0 and column = 0

Now the inner loop value of j is incremented to 1. So j = 1

At next iteration array[0][1] is checked. The element at this position is 5.5

if (maxValue < a[i][j]) is true because 1<5.5 so now value of maxValue becomes:

maxValue = 5.5

and

i = 0  j = 1

This way at each iteration of inner loop the columns are traversed and at each iteration of outer loop rows are traversed.

At next iteration element at array[1][0] is checked which is 4.5. This is not greater than maxValue so maxValue remains 5.5

At next iteration element at array[1][1] is checked which is 3. This is not greater than maxValue so maxValue remains 5.5 .

After both the loops end the statement:

return new Location(row,column,maxValue);

returns row , column and maxValue

where row = 0  column = 1 and maxValue = 5.5

So the output is:

The largest element in a two-dimensional array is: 5.5

The location of the largest element is at (0,1)

3 0
4 years ago
What device is used to transmit what is effectively a type of Morse code between stations?
IrinaVladis [17]
<h3>Its B 100% sure.....</h3>

Brainiest Please :)

6 0
3 years ago
What is the name of a button on a website?
zhuklara [117]
May I know which button?
5 0
3 years ago
What are two drawbacks of using netbook ? (Choose two)
nydimaria [60]

Answer:

D and C

Explanation:

I would say D and C because they don't have fast processors they normally only use Celerons. and normally they only have a 64GB internal SSD.

It's definitley not a because they are extremely portable and have amazing battery life

I don't think its B because they have small screens but you can also get them in bigger 14" variants which is normally the generic size.

5 0
3 years ago
James added a new video card and needs to get a power supply that will have enough power to run the new card. When researching t
Shtirlitz [24]

Answer:

the voltage it will need to give and take

Explanation:

it all depends on the amount of voltage the video card requires say the video card requires 150v you would have to buy a power supply that would be able to support that and all the other parts so you would buy a 550v power supply

3 0
3 years ago
Other questions:
  • Consider the following page reference string:
    12·1 answer
  • A network administrator wants to increase the speed and fault tolerance of a connection between two network switches. To achieve
    9·2 answers
  • If the__________ is/are out of balance, the driver will feel a pounding or shaking through the steering wheel.
    7·2 answers
  • What is the output <br>this is a computer science question ​
    8·1 answer
  • To use an imported image, simply drag it from the desktop onto the stage. true or false
    15·2 answers
  • What is a task that is not associated with loading existing data into a new ERP system.
    11·2 answers
  • Some of the ways we can resolve IPv4 address shortage
    15·1 answer
  • Which situation is the best choice for using telehealth?
    12·1 answer
  • What is a common misconception about Agile and DevOps?
    9·1 answer
  • In query design view you can add .............. to limit the number of records shown in the resulting datasheet
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!