Answer:
option B
Explanation:
The correct answer is option B
Seaming is an operation in which the edges are folded over another part to achieve the tight fit.
Seaming is generally used to join other parts together.
So, seaming is generally used for producing fluid-tight joints.
This process is used in the food industry on canned goods, metal roofing, and in the automotive industry.
Answer:
a) The slip coefficient is 0.9
b) Blade tip speed is 345.57 m/s
c) Stagnation temperature exiting the impellor is 416.84 k
d) Exit flow velocity is 84.88 m/s
e) Exit flow angle is 76.2°
f) Exit static temperature is 353.84 k
g) Impellor exit Mach number is 0.943
Explanation:
Flow at entry is axial α₁ = 0
Tagential velocity at entry 
= 0
Blade at exit is radial β₂ = 0
μ₂ = 
Answer:
5
Explanation:
The sum of the digits of the number is ...
(4+1+3)+(4+6+5)+(7+8+9) = 8+15+24 = 47
The sum of those digits is 4+7=11, and those digits sum to 1+1 = 2.
That is, the value of the number mod 9 (or 3) is 2.
The ones digit is odd, so the value of the number mod 2 is 1.
This combination of modulo values tells you the mod 6 result is 5.
_____
<em>Additional comment</em>
We can look at the (mod2, mod3) values of the numbers 0 to 5:
0 ⇒ (0, 0)
1 ⇒ (1, 1)
2 ⇒ (0, 2)
3 ⇒ (1, 0)
4 ⇒ (0, 1)
5 ⇒ (1, 2) . . . . the mod {2, 3} results we have for the number of interest.
This process of adding up the digits repeatedly is referred to as "casting out 9s." The result of it is the modulo 9 value of the number (with 0 mapped to 9). Checking the mod 9 result of arithmetic operations is one quick way to spot certain kinds of errors. It can also be used as part of a divisibility test for 3 or 9.
Answer:
Yes this claim is correct.
Explanation:
The shear stress at any point is proportional to the velocity gradient at any that point. Since the fluid that is in contact with the pipe wall shall have zero velocity due to no flow boundary condition and if we move small distance away from the wall the velocity will have a non zero value thus a maximum gradient will exist at the surface of the pipe hence correspondingly the shear stresses will also be maximum.
Answer:
the required diameter of the rod is 9.77 mm
Explanation:
Given:
Length = 1.5 m
Tension(P) = 3 kN = 3 × 10³ N
Maximum allowable stress(S) = 40 MPa = 40 × 10⁶ Pa
E = 70 GPa = 70 × 10⁹ Pa
δ = 1 mm = 1 × 10⁻³ m
The required diameter(d) = ?
a) for stress
The stress equation is given by:
A is the area = πd²/4 = (3.14 × d²)/4
Substituting the values, we get
d = (9.77 × 10⁻³) m
d = 9.77 mm
b) for deformation
δ = (P×L) / (A×E)
A = (P×L) / (E×δ) = (3000 × 1.5) / (1 × 10⁻³ × 70 × 10⁹) = 0.000063
d² = (4 × A) / π = (0.000063 × 4) / 3.14
d² = 0.0000819
d = 9.05 × 10⁻³ m = 9.05 mm
We use the larger value of diameter = 9.77 mm
