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2 years ago

What are some possible reasons for the sudden development of the cell theory

Engineering

1 answer:

11Alexandr11 [23.1K]2 years ago

4 0

Answer:

microscope technology improved. Schleiden made his discovery, that caught the interest of other scientists, who went on to add new discoveries.

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Explain what are rafters?

RSB [31]

Answer:

rafter is a structural component that is used as part of a roof construction. There are also different types of rafters

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2 years ago

An aircraft is flying at 300 mph true airspeed has a 50 mph tailwind. What is its ground speed?

Free_Kalibri [48]

Answer:

304.13 mph

Explanation:

Data provided in the question :

The Speed of the flying aircraft = 300 mph

Tailwind of the true airspeed = 50 mph

Now,

The ground speed will be calculated as:

ground speed = $\sqrt{300^2+50^2}$

The ground speed = $\sqrt{92500}$

The ground speed = 304.13 mph

Hence, the ground speed is 304.13 mph

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3 years ago

Determine the percent increase in the nominal moment capacity of the section in Problem 2 when including compression steel at to

sergejj [24]

Explanation:

Please kindly share your problem two with us as to know the actual problem we are dealing with, the question looks incomplete

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3 years ago

Which of the following are tips to help a speaker use their own voice?

djverab [1.8K]

D) All of the above.

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3 years ago

Read 2 more answers

A rigid, well-insulated tank of volume 0.9 m is initially evacuated. At time t = 0, air from the surroundings at 1 bar, 27°C beg

Eva8 [605]

Answer:

$\dot{w}$ = -0.303 KW

Explanation:

This is the case of unsteady flow process because properties are changing with time.

From first law of thermodynamics for unsteady flow process

$\dfrac{dU}{dt}=\dot{m_i}h_i+\dot{Q}-\dot{m_e}h_i+\dot{w}$

Given that tank is insulated so $\dot{Q}=0$ and no mass is leaving so

$\dot{m_e}=0$

$\int dU=\int \dot{m_i}h_i\ dt-\int \dot{w}\ dt$

$m_2u_2-m_1u_1=(m_2-m_1)h_i- \dot{w}\Delta t$

Mass conservation $m_2-m_1=m_e-m_i$

$m_1,m_2$ is the initial and final mass in the system respectively.

Initially tank is evacuated so $m_1=0$

We know that for air $u=C_vT ,h=C_p T$ , $P_2v_2=m_2RT_2$

$m_2=0.42 kg$

So now putting values

$0.42 \times 0.71 \times 730=0.42\times 1.005\times 300- \dot{w} \times 300$

$\dot{w}$ = -0.303 KW

3 0

3 years ago