To solve the problem it is necessary to use the concepts related to frictional dissipation per unit mass, energy balance equation and Volumetric flow rate.
The frictional dissipation per unit mass is defined as
Where,
Superficial velocity of fluid
Fluid viscoisty
Porosity
Fluid density
L = Packed bed length
= Effective particle diameter
Through energy balance equation we have that
Neglect the change in velocity and pressure and the work done we have,
We have also that de grade is defined as
With our values and replacing at the previous equation we have,
Previously with the given depth and height we have to
Therefore the Volumetric flow rate,
Therefore the desired volumetric flow rate is 2456gal/min
Answer:
5.118 m^3/hr
Explanation:
Given data:
viscosity of cell broth = 5cP
cake resistance = 1*1011 cm/g
dry basis per volume of filtrate = 20 g/liter
Diameter = 8m , Length = 12m
vacuum pressure = 80 kpa
cake formation time = 20 s
cycle time = 60 s
<u>Determine the filtration rate in volumes/hr expected fir the rotary vacuum filter</u>
attached below is a detailed solution of the question
Hence The filtration rate in volumes/hr expected for the rotary vacuum filter
V' = ( ) * 1706.0670
= 5118.201 liters ≈ 5.118 m^3/hr
Answer:
Midnight on the birthday. Hope this helps!
Answer:
D life time of safe driving I am guessing on this one but pretty sure if you look at the question and answers
Explanation:
Answer:
-0.89%
Explanation:
Assuming a proportional relationship between EMF and Celsius temperature, the measured value of EMF at 100 °C will be interpreted as a temperature of ...
T/5.268 = 400/21.846
T = 5.268(400/21.846) ≈ 96.457 . . . . °C
The error as a fraction of full scale is ...
(96.457 -100)/400 × 100% ≈ -0.886%
The error at 100 °C is about -0.89% of full scale.