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3 years ago

6

A standard carbon resistor has a gold band to indicate + 5% tolerance. If its resistance is 3,500 , what are the upper and lower

limits for its resistance? OA . 3495 - 3505 2 OB. 3300 Q - 3600 0 OC. 3325 N - 3675 OD 3450 - 35500

1 answer:

Lapatulllka [165]3 years ago

7 0

Answer:

C. 3325 Ω - 3675 Ω

Explanation:

5% of 3500 Ω is ...

0.05 × 3500 = 175

The lower limit is this amount less than the nominal value:

3500 -175 = 3325

The upper limit is the nominal value plus the tolerance:

3500 +175 = 3675

The lower and upper limits are 3325 Ω and 3675 Ω, respectively.

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Answer:

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Given data:

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v = 0.8409 m^3/ kg

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$\dot m = \frac{A_1 V_1}{v} = \frac{\pi 8^2\times 12}{4\times 0.8049}$

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Air modeled as an ideal gas enters a combustion chamber at 20 lbf/in.2

motikmotik

Answer:

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Explanation:

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Flow rate of the mass $m = 230.556 \frac{lbm}{s}$

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$\to \bar{R} = 1545 \ ft \frac{lbf}{lbmol ^{\circ} R}\\\\ \to M= 28.97 \frac{lb}{\bmol}\\\\ \to pv=RT \\\\\to v= \frac{\frac{\bar{R}}{M}T}{p}$

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$V= \frac{mv}{A}$

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