Answer:
The average acceleration of train is 
Step-by-step explanation:
We have,
A train that slows down from 15 m/s to 8.6 m/s in 1.2 s. It means that 15 m/s is its initial velocity and 8.6 m/s is its final velocity.
It is required to find the average acceleration of the train.
The average acceleration of train is . Negative signs shows that the train is decelerating.
Answer:
Step-by-step explanation:
Depending on whether or not the g(x) is x^2 or 2x, I have both ways.
If g(x) is x^2 - 9...
--> (3x^2 + 2) - (x^2 - 9) = 2x^2 + 11
If g(x) is 2x...
--> (3x^2 + 2) - (2x - 9) = 3x^2 - 2x + 11
Hope this helps!
Answer:
x = 8
Step-by-step explanation:
3 (x - 5) + 7x = 65
3x - 15 + 7x = 65
10x - 15 = 65
10x = 80
x = 8
Answer:
okay, you have pay special attention to time.i.e 60secs = 1 minute, 60 minutes = 1 hour, 24 hours in one day, and 7 days in one week. No. of seconds in one week we are told is 6.1048 x 10 ^5 seconds.
Step-by-step explanation:
s = d/t [ speed = distance/time]
therefor, rearranging, we get d = s x t
Since speed = 2.998*10^5 Km/s and time = 6.048^10^5
d = (2.998 x 10^5) x (6.048 x10^5) = (2.998 x 6.048) x 10 ^(5+5)
d = 18.131904 X 10^10 km
d = approximately 18.132 x 10^10 km (to 3 decimal places)
23 to the 3 because I just took it
