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Andrews [41]
4 years ago
8

Can u help me in this pls

Mathematics
1 answer:
Misha Larkins [42]4 years ago
6 0

Answer:

The first one is correct I believe.

Step-by-step explanation:

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Sandy made 8 friendship bracelets she gave 1 bracelet to her best friend and 5 to to her friends in the tennis team
Oduvanchick [21]

Answer:

2

Step-by-step explanation:

1/8 2/8 3/8 4/8 5/8 6/8 7/8 8/8

8/8-6/8=2/8

8 0
4 years ago
Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set
KATRIN_1 [288]
\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}

6 0
1 year ago
EASY MATH QUESTION <br><br> PLEASE HELP
Juli2301 [7.4K]
F(x)=3x^2-5 when x=-11
f(-11)=3(-11)^2-5
f(-11)=-33^2-5
f(-11)=1089-5
f(-11)= 1084

Hope this could help!
3 0
3 years ago
A publisher requires 2∕3 of a page of advertisements for every 5 pages in a magazine. If a magazine has 98 pages, to the nearest
Eddi Din [679]

Answer:

\boxed{13} pages

Step-by-step explanation:

Divide the total number of pages by 5 to get how many sets of every 5 pages will contain 2/3 of a page of advertisements.

\frac{98}{5} = 19.6

Multiply this value by \frac{2}{3} to get the total number of pages.

19.6 * \frac{2}{3} \approxeq 13 pages

4 0
3 years ago
Of the 80 students in the student body, 60 voted for the winning candidate. What percent voted for the winning candidate
Olin [163]

Answer:

20 studenti fac laba on a romania

6 0
3 years ago
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