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Andrews [41]
4 years ago
8

Can u help me in this pls

Mathematics
1 answer:
Misha Larkins [42]4 years ago
6 0

Answer:

The first one is correct I believe.

Step-by-step explanation:

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A swimming pool in the shape of a right rectangular prism is filled with water. The pool is 25 yards long, 10 yards wide, and 2
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Answer:

10400 lb

Step-by-step explanation:

First find the volume of the water in the pool:  It is V = (length)(width)(height).

Here, V = (25 yds)(10 yds)(2/3 yd), or (500/3  yds³.

Then multiply this result by the unit rate (62.4 lb / ft³).  

The result is  10400 lb.  This is the weight of the water in the pool.

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The value of x is 10. What is the measurement of angle UP?<br> A.64<br> B.52<br> C.116<br> D.40
worty [1.4K]

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116

Step-by-step explanation:

12(10) -4

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4 years ago
What is JL? pls help
mrs_skeptik [129]

Answer:

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3 0
3 years ago
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The diagonals of a rhombus are 14 and 48cm. Find the length of a side of the rhombus.
FromTheMoon [43]

Step-by-step explanation:

Let ABCD be a rhombus. So, AC (AC = 14 cm) and BD (BD=48 cm) will be its diagonals. Let us assume that diagonals are intersecting at point O.

Since, diagonals of a rhombus are perpendicular bisector.

\because \: OA  =  \frac{1}{2}  \times AC \\  \\   \therefore \: OA  =  \frac{1}{2}  \times 14 \\  \\   \huge \red{ \boxed{\therefore \: OA  =  7 \: cm}} \\  \\ \because \: OB  =  \frac{1}{2}  \times BD \\  \\ \therefore \: OB  =  \frac{1}{2}  \times 48 \\  \\ \huge \red{ \boxed{\therefore \: OB  = 24 \: cm}} \\  \\ In \:  \triangle OAB, \:  \:  \angle AOB=90° \\  \therefore \: by \: Pythagoras \: Theorem \\ AB= \sqrt{OA^2 +OB^2 }  \\  =  \sqrt{7^2 +24^2 } \\ =  \sqrt{49+576 } \\ =  \sqrt{625 } \\  \huge \orange{ \boxed{\ \therefore \:AB= 25 \: cm.}}

Hence, length of a side (or all) is 25 cm.

3 0
4 years ago
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