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dexar [7]
3 years ago
12

Solve to find missing length

Mathematics
1 answer:
shutvik [7]3 years ago
6 0

Answer:

m = 4\sqrt 3\\n = 6

Step-by-step explanation:

\tan \: 60 \degree =  \frac{n}{2 \sqrt{3} }  \\  \\  \sqrt{3}  = \frac{n}{2 \sqrt{3} }   \\  \\ n =  \sqrt{3}  \times 2 \sqrt{3}  \\  \\ n = 2 \times 3 \\  \\ \huge \red { \boxed{ n = 6}} \\  \\  \cos \: 60 \degree =  \frac{2 \sqrt{3} }{m}  \\  \\  \frac{1}{2}  = \frac{2 \sqrt{3} }{m}   \\  \\ m = 2 \times 2 \sqrt{3}  \\  \\ \huge \purple{ \boxed{ m = 4\sqrt{3} }}

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