Question

Given triangle ABC, A = 120°, a = 8, b = 3; determine B to the nearest whole degree. Do not use a decimal point or extra spaces in the answer or it will be marked incorrect.

Answer 1

The answer is 45
8/120. = 3/x cross multiply

Answer 2

Answer:

∠B = 19°

Step-by-step explanation:

In the triangle ABC,

                       ∠A = 120° side a = 8 and b = 3

We have to find angle B.

We will apply sine rule in this triangle

$\frac{a}{sinA}=\frac{b}{sinB}$

$\frac{8}{sin120*}=\frac{3}{sinB}$

8 sin B = 3 sin 120°

Sin b = $\frac{3}{8}$ (sin 120°) =  $\frac{3\times 0.866}{8}$ = 0.3248

B = sin⁻¹ (0.3248)

  = 18.95 ≈ 19°

Therefore, ∠B = 19° is the answer.