Answer: option D. 2x^2 + (3/2)x - 5
Explanation:
1) polynomials given:
f(x) = x/2 - 2 and g(x) = 2x^2 + x - 3
2) question: find (f + g) (x)
That means that f(x) + g(x), so you have to add up the two polynomials given.
3) x/2 - 2 + 2x^2 + x - 3
4) Combine like terms:
a) terms with x^2: you only have 2x^2, so it is not combined with other term.
b) terms with x: x/2 + x
that is a sum of fractions: x/2 + x = [x + 2x] / 2 = 3x / 2 = (3/2)x
c) constant terms: - 2 + (-3) = - 2 - 3 = - 5
5) Result: 2x^2 + (3/2)x - 5
That is the option d.
Answer:
parts A answer D) -5.400divided by 8
and for part B is c) -675
Step-by-step explanation:
mark me as brainlest pliz
Answer:
k = (6/15)
Step-by-step explanation:
The equation is:
6*(x + 1) + 2 = 3*(k*5*x + 1) + 3
To have no solutions, we need to have something like:
x + 7 = x + 4
where we can remove x in both sides and end with
7 = 4
So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.
First, let's try to simplify our equation:
6*(x + 1) + 2 = 3*(k*5*x + 1) + 3
6*x + 6 + 2 = 3*k*5*x + 3*1 + 3
6*x + 8 = 15*k*x + 6
if 15*k = 6, then the system clerly has no solution.
then:
k = 6/15
then we get:
6*x + 8 = (6/15)*15*x + 6
6*x + 8 = 6*x + 6
8 = 6
The system has no solutions.
I am not 100% positive but from what I remember learning I think the answer you are looking for on the first question is C.
