Question # 14
Given the numbers
10 11 12 13 14 15 16 17 18 19 20
Let 'x' be the number
The condition breakdown:
I am less than 20.
- So the number 'x' must be less than 20 i.e. x < 20
I am more than 13.
- So the number 'x' must be greater than 13 i.e. x > 13
I am less than 17.
- So the number 'x' must be less than 17 i.e. x < 17
Finally:
I am 4 more than 12
i.e. 12+4 = 16
Thus, the number is x = 16
Question # 15
Part a)
Given the numbers
10 11 12 13 14 15 16 17 18 19 20
Let 'x' be the number
The condition breakdown:
I am more than 10.
I am less than 20.
I am more than 12.
I am less than 15.
As the numbers left after all the conditions are fulfilled are 13 and 14.
- But the last condition is, of the numbers that left, the number is greater than all the remaining numbers.
So, from the remaining number 13 and 14;
14 > 13
Thus, the number x = 14
Part b)
Drawing the number 14 in the place value:
Chart
Tens Ones
1 4
Hope this will help u....
<u>Corrected Question</u>
The solution to an inequality is represented by the number line. How can this same solution be written using set-builder notation? {x | x > }
Answer:
Step-by-step explanation:
Given an inequality whose solution is represented by the number line attached below.
We observe the following from the number line
There is an open circle at 3, therefore the solution set does not include 3. (We make use of > or < in cases like that)
The arrow is pointed towards the right. All points to the right of 3 are greater than 3, therefore:
The solution in the number line can be written using set-builder notation as:
Answer: -8r+12
Step-by-step explanation:
Answer:
Step-by-step explanation:
It’s c
