The sister catches up Jeff after 2 hours
Step-by-step explanation:
We can write Jeff's position and his sister position at time t using the following expressions:
- Jeff position:
where:
7 is the initial position of Jeff when his sister sarts chasing him
2.5 is Jeff's velocity (in miles/hour), so its position increases by 2.5 miles for each hour
t is the time measured in hours
- Sister position:
where
6 is the sister velocity (her position increases by 6 miles for every hour)
t is the time measured in hours
The sister catches up Jeff when the two positions are equal, so
And solving for t,
So, the sister catches Jeff after 2 hours.
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The answer is 204. Your well
<span>(2.3 x 10^-3)(3 x 10^8)
=(</span>2.3 x 3)(10^-3 x 10^8)
= 6.9 x 10^5
hope it helps
The expression can be simplified as:
k^3(k7/5)^-5
= k^(3+-5) * (7/5)^-5
(Collecting the powers of k at one side and the constants at other side)
= k^-2 * (5/7)^5
(Solving thr integer powers)
= k^-2 * (3125/16807)
(50,45)(125,37.50)
slope(m) = (37.50 - 45) / (125 - 50) = -7.5/75 = -0.1
y = mx + b
slope(m) = -0.1
(50,45)...x = 50 and y = 45
now we sub and find b, the y int
45 = -0.1(50) + b
45 = - 5 + b
45 + 5 = b
50 = b
so ur equation is : y = -0.1x + 50
so it the staff sells 150 yearbooks...
y = -0.1x + 50
y = -0.1(150) + 50
y = -15 + 50
y = 35 <== price per yearbook
