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TEA [102]
3 years ago
6

Find an equation of the parabola that has the indicated vertex and whose graph passes through the given point

Mathematics
1 answer:
vichka [17]3 years ago
3 0
Equation of a parabola with vertex at (2, -1) is
y = a(x - 2)^2 - 1

Using the given point: -3 = a(4 - 2)^2 - 1
-2 = a(2)^2
4a = -2
a = -1/2

Therefore, required equation is
y = -1/2(x - 2)^2 - 1
y = -1/2(x^2 - 4x + 4) - 1
y = -1/2x^2 + 2x - 2 - 1
y = -1/2x^2 + 2x - 3
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I asked more than 10 times Still no steps to a solution
Alisiya [41]

Answer:

C 200

Step-by-step explanation:

It does not appear to be LINEAR so

Start with :

pulse rate = y = 73e^kx  

sub in x = .7      when y = 155

155 = 73 e^(.7 * k)

ln ( 155/73)  =  .7k

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for x = 0.9 :

pulse rate  =  y = 73 e^(1.07567 * .9)  = ~ 192      so I expect answer is 200

8 0
2 years ago
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Answer:

Its C

Step-by-step explanation:

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8 0
3 years ago
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