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Naddik [55]
3 years ago
5

Write an equation for sidewalk one in slope intercept form.

Mathematics
1 answer:
sveta [45]3 years ago
8 0
X   y
2   7
0   3
I figured out how to do it.
2-0=2
7-3=4
4/2=2 therefore the gradient is 2.
Now we need the y intercept which is already given (the y intercept is when x=0) when x equals 0 x=3 so the equation of the line is:
y=2x+3

Hope this helps :)
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What is the minimum y-value after which the exponential function will always be greater than the linear function? y = 1 y = 3 y
Stells [14]

Answer:

y = 4.

Step-by-step explanation:

I suppose that this question relates to the image that can be seen below.

In the image, the green line represents the exponential function and the blue line represents the linear function.

The y-value after which the exponential function will always be greater than the linear function is the y-value where bot graphs intersect, such that after that point, the blue line starts increasing fast, and is always above the green line.

In this case, this point is the second intersection, and we can see that this intersection happens in the point (2, 4)

Remember that the usual notation for points is (x, y).

Then the y-value after which the exponential function will always be greater than the linear function is y = 4.

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3 years ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm8,0)(±8,0)left parenthesis, plus minus, 8, comma,
mario62 [17]

Answer:

The equation of the ellipse is \frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1

Step-by-step explanation:

The standard form of the equation of an ellipse with center (0 , 0) is

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 , where

  • The coordinates of the vertices are (± a , 0)  
  • The coordinates of the foci are (± c , 0) , where c ² = a² - b²  

∵ The ellipse is centered at the origin

∴ The center of it is (0 , 0)

∵ It has foci at (± 8 , 0)

- The coordinates of the foci are (± c , 0)

∴ c = ±8

∵ It has Vertices at (± 17 , 0)

- The coordinates of the vertices are (± a , 0)

∴ a = ±17

∵ c² = a² - b²

- Substitute the values of c and a to find b

∴ (8)² = (17)² - b²

∴ 64 = 289 - b²

- Add b² to both sides

∴ b² + 64 = 289

- Subtract 64 from both sides

∴ b² = 225

- Take √  for both sides

∴ b = ± 15

∵ The equation of the ellipse is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

- Substitute the values of a and b in it

∴ \frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1 ⇒ \frac{x^{2}}{289}+\frac{y^{2}}{225}=1  

∴ The equation of the ellipse is \frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1

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Answer:

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