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lozanna [386]
3 years ago
7

4. From a faculty of six professors, six associate professors, ten assistant professors, and twelve instructors, a committee of

size six is to be selected. What is the probability that the number of selections include exactly two professors?
Mathematics
1 answer:
Degger [83]3 years ago
8 0

Answer:

P=0.228

Step-by-step explanation:

We know that from a faculty of six professors, six associate professors, ten assistant professors, and twelve instructors, a committee of size six is to be selected.

Therefore, we have 34 people.

We calculate the number of possible combinations:

C^{34}_6=\frac{34!}{6!(34-6)!}=1344904\\

Of the 6 professors we choose 2, and of the other 28 people we choose 4.

We calculate the number of favorable combinations:

C_2^6\cdot C_4^{28}=\frac{6!}{2!(6-2)!}\cdot \frac{28!}{4!(28-4)!}=15\cdot 20475=307125\\

Therefore, the probability is:

P=\frac{307125}{1344904}=0.228

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A population of 50 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain up to 500 deer.
rewona [7]

Answer:

p1 = 70 deer

p2 = 98 deer

Step-by-step explanation:

We use the population growth expression:

N(t)=N_0\,(1+r)^t

which in our case renders:

N(t)=N_0\,(1+r)^t\\N(t)=50\,(1+0.4) ^t\\N(t)=50\,(1.4) ^t

Therefore, after 1 year the population would be:

N(1)=50\,(1.4) ^1=70

giving a total of 70 deer

and after two years, it would be:

N(2)=50\,(1.4) ^2=98

8 0
3 years ago
Please help, basic Algebra question
Tju [1.3M]

Answer:

The given expression  (\frac{5}{6} a^{9}p^{5})  ^{3} = \frac{125}{216}  \times a^{(27) } \times p^{(15)}

Step-by-step explanation:

Here, the given expression is:  (\frac{5}{6} a^{9}p^{5})  ^{3}

Now, starting from the outer most bracket.

As we know :

(abc)^{n}   = (a)^{n} \times (b)^{n}  \times (c)^{n}

and (a^m)^{n} = a^{(m \times n)}

⇒ (\frac{5}{6} a^{9}p^{5})  ^{3} = (\frac{5}{6})^{3} \times (a^{9})^{3}   \times (p^{5}) ^{3}\\

=\frac{125}{216}  \times (a)^{(9\times3) } \times (p)^{(5 \times 3)}\\= \frac{125}{216}  \times a^{(27) } \times p^{(15)}

Hence, the given expression  (\frac{5}{6} a^{9}p^{5})  ^{3} = \frac{125}{216}  \times a^{(27) } \times p^{(15)}

7 0
3 years ago
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Romashka [77]
1/8 of the cake has not been eaten.
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3 years ago
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1285 students went on a field trip six buses were filled with the same number of students and seven other student travel in coll
Mademuasel [1]
213 students were in each bus
6 0
3 years ago
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Find x and y please!!! I need help!!
jonny [76]

Answer

Step-by-step explanation:

(15x-8y)=52

180=90+52+x

x=38

System of equations:

15x-8y=52

6x+14y=38

y=-6.5+15/8x

6x+14(-6.5+15/8x)=38

6x-91+26.25x=38

32.25x=129

x=4

15(4)-8y=52

60-8y=52

-8y=-8

y=1

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2 years ago
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