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Mandarinka [93]
3 years ago
5

Zimway Inc is a small-scale manufacturer of linen. Couture Corp, a big apparel brand, purchases linen from Zimway in large quant

ities. Zimway, otherwise, has very few clients, and most of them purchase linen occasionally and in minimal quantities. Therefore, business ties with Couture is crucial for Zimway's survival and success. In the context of the specific environment, which of the following concepts is illustrated in the scenario?
A) Buyer dependence
B) Supplier dependence
C) Regulator dependence
D) Internal dependence
Business
1 answer:
Vikentia [17]3 years ago
7 0

Answer:

The correct answer is letter "A": Buyer dependence.

Explanation:

Buyer dependence refers to the tied relationship between a buyer and the retailer or a retailer and the manufacturer. Without the purchase of the buyer or the retailer -according to what applies, the manufacturer could not continue operations since there would not be sales, meaning the company will have to stop the business due to the lack of profit.

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Answer: The values are missing below are the values

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answer :

a) $5

b) -$5 ( loss )  

Explanation:

From the perspective of the long position for each of the two options  upon expiration

a) For $105

for the long position ( long call ) since the expired price > than the exercise price

i.e. $105 > $100 the profit = $105 - $100 = $5

b) For $95

For the long position ( long call ) since the expired price < than the exercise price

i.e. $95 < $100 the profit = $95 - $100 =  - $5  ( a loss is incurred )

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That a person can buy a product or service in.
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Got it right and good luck kid

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The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almana
storchak [24]

Answer:

a) P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

b) P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

c) P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores for critical reading of a population, and for this case we know the distribution for X is given by:

X \sim N(502,100)  

Where \mu=502 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(502-10 < \bar X < 502+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

Part b

Let X the random variable that represent the scores for Math of a population, and for this case we know the distribution for X is given by:

X \sim N(515,100)  

Where \mu=515 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(515-10 < \bar X < 515+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

Part c

Let X the random variable that represent the scores for Writing of a population, and for this case we know the distribution for X is given by:

X \sim N(494,100)  

Where \mu=494 and \sigma=100

We select a sample of size n=100, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{100}}=10)

And for this case we want this probability:

P(494-10 < \bar X < 494+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

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Control happens once competitor brokers comply with a typical worth for sales commissions, fees, or management rates. The Sherman just Act forbids any style of control in any business.

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The just prohibition on fixing commission rates means that 2 or additional realty companies might not agree on the commission rate that everyone can charge. As noted earlier, control may be a violation of just laws.

To learn more about tie-in agreements, visit here

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