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3 years ago

Given the information below, write the equation in Standard Form.

Mathematics

1 answer:

Sergio [31]3 years ago

3 0

Answer:

The standard form of the equation of the parabola is (y + 2)² = 8 (x - 3)

Step-by-step explanation:

The standard form of the equation of a parabola is (y - k)² = 4p (x - h), where

The vertex of the parabola is (h , k)
The focus is (h + p, k)

∵ The vertex of the parabola is (3 , -2)

∴ h = 3 and k = -2

∵ The focus is (5 , -2)

∴ h + p = 5

- Substitute h by 3 to find p

∵ 3 + p = 5

- Subtract 3 from both sides

∴ p = 2

∵ The standard form of the equation of the parabola is (y - k)² = 4p (x - h)

- Substitute the values of h , k , and p in the equation

∴ (y - -2)² = 4(2) (x - 3)

∴ (y + 2)² = 8 (x - 3)

The standard form of the equation of the parabola is (y + 2)² = 8 (x - 3)

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Consider the differential equation x^2 y''-xy'-3y=0. If y1=x3 is one solution use redution of order formula to find a second lin

Anastasy [175]

Suppose $y_2(x)=y_1(x)v(x)$ is another solution. Then

$\begin{cases}y_2=vx^3\\{y_2}'=v'x^3+3vx^2//{y_2}''=v''x^3+6v'x^2+6vx\end{cases}$

Substituting these derivatives into the ODE gives

$x^2(v''x^3+6v'x^2+6vx)-x(v'x^3+3vx^2)-3vx^3=0$

$x^5v''+5x^4v'=0$

Let $u(x)=v'(x)$ , so that

$\begin{cases}u=v'\\u'=v''\end{cases}$

Then the ODE becomes

$x^5u'+5x^4u=0$

and we can condense the left hand side as a derivative of a product,

$\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0$

Integrate both sides with respect to $x$ :

$\displaystyle\int\frac{\mathrm d}{\mathrm dx}[x^5u]\,\mathrm dx=C$

$x^5u=C\implies u=Cx^{-5}$

Solve for $v$ :

$v'=Cx^{-5}\implies v=-\dfrac{C_1}4x^{-4}+C_2$

Solve for $y_2$ :

$\dfrac{y_2}{x^3}=-\dfrac{C_1}4x^{-4}+C_2\implies y_2=C_2x^3-\dfrac{C_1}{4x}$

So another linearly independent solution is $y_2=\dfrac1x$ .

3 0

3 years ago

Help please

Leno4ka [110]

H = hrs she worked
p = phone calls she answered

h x 10 + p x .25 = maggies earnings

Part A
h x 10 + 60 x .25 = 115

Part B
h x 10 + 15 = 115 (multiplied 60 x .25)
h x10 = 100 (subtracted 15 from each side of the equation)
h = 10 (divided 10 into each side)

Part C
10 hrs

Hope this helps

3 0

3 years ago

Read 2 more answers

Peter spent half the money on his gift card and coffee and he loaded another $10 on the gift card how much was on the gift card

cestrela7 [59]

Answer:

$80 was on the gift card to begin with

Step-by-step explanation:

Let the initial money be x

Peter spent (1/2)*x

Peter added 10

Before adding more money on the gift card Peter had x -(1/2)x left on the gift card which is (1/2)x

After loading more money Peter had (1/2)x + 10

(1/2)x = 40 (money spent by Peter)

x/2 = 40

x = 80

6 0

4 years ago

Help me please guys

Jlenok [28]

Answer:

(9,6)

Step-by-step explanation:

You just take one of the (x,y) pairs and switch the numbers with each other so it's like (y,x)

5 0

3 years ago

Read 2 more answers

Anna sells candy apples at her yard sale. She wants to earn more than $40. She sells the apples for $2 each and has earned $26.

densk [106]

Answer:

Step-by-step explanation:

Because if 1 apple=2$ then she need to sell 20 apples she now has 26$ meaning she has sold 13 of them so 26$

She needs 14 more$ remember the rule 1 apple=2$ so if she needs 14 more $ then that means 7 more apples=14$ And there's your answer 7 more apples.

Hope this helps have a great afternoon:)

7 0

2 years ago