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LiRa [457]
3 years ago
7

Given the information below, write the equation in Standard Form.

Mathematics
1 answer:
Sergio [31]3 years ago
3 0

Answer:

The standard form of the equation of the parabola is (y + 2)² = 8 (x - 3)

Step-by-step explanation:

The standard form of the equation of a parabola is (y - k)² = 4p (x - h), where

  • The vertex of the parabola is (h , k)
  • The focus is (h + p, k)

∵ The vertex of the parabola is (3 , -2)

∴ h = 3 and k = -2

∵ The focus is (5 , -2)

∴ h + p = 5

- Substitute h by 3 to find p

∵ 3 + p = 5

- Subtract 3 from both sides

∴ p = 2

∵ The standard form of the equation of the parabola is (y - k)² = 4p (x - h)

- Substitute the values of h , k , and p in the equation

∴ (y - -2)² = 4(2) (x - 3)

∴ (y + 2)² = 8 (x - 3)

The standard form of the equation of the parabola is (y + 2)² = 8 (x - 3)

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If a pentagon is regular, then all of the sides are the same length. This means that

5x-4=2x+11 \iff 5x-2x = 11+4 \iff 3x=15 \iff x = 5

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5x-4 = 25-4=21,\quad 2x+11=10+11=21

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3 years ago
A new youth sports center is being built in a safe harbor. The perimeter of the rectangular playing field is 510 yards. The leng
podryga [215]

Answer:

<h2>L=203 yards</h2><h2>W=52 yards</h2>

Step-by-step explanation:

Step one:

given data

perimeter= 510 yards

let the width be x, width=x

length= (4x-5)-----quadruple mean 4 times

Step two:

the expression for perimeter is

P=2L+2W

510=2(4x-5)+2x

510=8x-10+2x

510+10=8x+2x

520=10x

divide both sides by 10

x=520/10

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4 0
3 years ago
7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?
loris [4]

Answer: a. Radius of circle = \sqrt{85}

b. The equation of this circle : (x-3)^2+(y-10)^2=85

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = \sqrt{(12-3)^2+(12-10)^2}

Radius of circle = \sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}

i.e. Radius of circle = \sqrt{85}

b. Equation of a circle = (x-h)^2+(y-k)^2=r^2 , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= \sqrt{85} , we get

(x-3)^2+(y-10)^2=(\sqrt{85})^2

(x-3)^2+(y-10)^2=85

∴  The equation of this circle :(x-3)^2+(y-10)^2=85

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Pythagorean theorem

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