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galben [10]
3 years ago
13

Factor. 2x-18. Please help <3

Mathematics
2 answers:
Paladinen [302]3 years ago
6 0
2x - 18

2(x-9) is your factored equation

If you want to solve for x... set 2(x-9)=0 and x=9
AveGali [126]3 years ago
3 0
<span><span>2x</span>−18</span>=2(x−9)
the answer is 2(x-9)
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The measure of two supplementary angles are 12q-9 and 8q+14 find the measures of the angles
Gwar [14]
First choose 1 equation and set it equal to 180 because supplementary angles equal up to 180 degrees. 

12q - 9 =180                                                              

Now solve for q.

12q - 9 +9 = 180 + 9

12q = 189

12q/12 = 18912

q = 15.75

now subtract 15.75 from 180

180.00 - 15.75 = 164.25

Your angles equal to 164.25 and 15.75 degrees.

4 0
3 years ago
How do i start this problem off?
Zinaida [17]
First recognize that you have complementary angles which means the angles will add up to 90 degrees


that means 64+2x+6 =90

solve for x
3 0
3 years ago
Read 2 more answers
If<br> 5 , 3 = 28<br> 9 , 1 = 810<br> 8 , 7 = 115<br> 6 , 2 = 48<br> then <br> 7 , 5 = ?
Rom4ik [11]

Answer:

212

Step-by-step explanation:

<u>Rule</u>

  • Subtract the 2nd number from the first to obtain the first digit(s) of the answer.
  • Add the 2nd number to the 1st to obtain the last digit(s) of the answer.

5 - 3 = 2

5 + 3 = 8

Therefore: 28

9 - 1 = 8

9 + 1 = 10

Therefore: 810

8 - 7 = 1

8 + 7 = 15

Therefore: 115

6 - 2 = 4

6 + 2 = 8

Therefore: 48

7 - 5 = 2

7 + 5 = 12

Therefore: 212

6 0
2 years ago
Read 2 more answers
Multiply 9 times 43 using the area model label the model
quester [9]

Answer:

387

Step-by-step explanation:

6 0
2 years ago
Simplify (-2x^4y^-3)^4
elixir [45]

Answer:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  =  \frac{16 {x}^{16}}{ {y}^{12} }

Step-by-step explanation:

We want to simplify:

( - 2 {x}^{4} {y}^{ - 3} )^{4}

We need to apply the exponential property for products of powers.

Recall that:

( {a}^{m}  \times  {a}^{n} )^{p}  =  {a}^{mp}  \times  {a}^{np}

We apply this rule to get:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  = ( { - 2)}^{4} x \times {x}^{16}  \times {y}^{ - 12}

This simplifies to:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  = 16 {x}^{16}  \times {y}^{ - 12}

We rewrite as positive index to get:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  =  \frac{16 {x}^{16}}{ {y}^{12} }

7 0
3 years ago
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