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3 years ago

The sum of two numbers is 62, and their difference is 12. What are the numbers?

2 answers:

6 0

X+y=62 ; x-y=12 Solve for x in one equation and plug that value into the other equation. ===> x=12+y ; 12+y+y=62 Subtract 12 to both sides (2y=50), then divide by 2 to find y (y=25). Now, plug 25 as y into x=12+y, getting x=37. Your two numbers are 37 and 25.

Bas_tet [7]3 years ago

3 0

Answer: The required numbers are 37 and 25.

Step-by-step explanation: Given that the sum of two numbers is 62 and their difference is 12.

We are to find the numbers.

Let x and y represents he given numbers.

Then, according to the given information, we have

$x+y=62~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\x-y=12~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Adding equations (i) and (ii), we get

$(x+y)+(x-y)=62+12\\\\\Rightarrow 2x=74\\\\\Rightarrow x=\dfrac{74}{2}\\\\\Rightarrow x=37.$

And, from equation (i), we get

$37+y=62\\\\\Rightarrow y=62-37\\\\\Rightarrow y=25.$

Thus, the required numbers are 37 and 25.

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