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3 years ago

10

Mike says that 3/3 of his fraction model is shaded blue. Ryan says that 6/6 of the same model is shaded blue. Are the two fracti

ons equivalent? if so, what is another equivalent fraction?

2 answers:

MArishka [77]3 years ago

8 0

Yes they are both equivalents because they are whole's and some examples would be 8/8,9/9,4/4. and 5/5 because they are all whole's 7 out of 7 pieces of pizza is the whole pizza.

miskamm [114]3 years ago

5 0

Yes, they are equivalent. They both equal 1.
Divide 3 by 3, then 6 by 6, you would get 1 from both fractions.

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Write a paragraph explaining how to solve 429 x 35 !

d1i1m1o1n [39]

1. lay your numbers out

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3 years ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points (-3,1) and (2,-1) is $y=-\frac{2}{5}x-\frac{1}{5}$

8 0

2 years ago

How to find the square root of complex numbers?? Find the square root of (6+8i) ??

ivann1987 [24]

Answer:

$2 \sqrt{2} + i \sqrt{2}$

Step-by-step explanation:

The square of a complex number is a complex number. Here, we have:

${(a + bi)}^{2} = 6 + 8i$

${a}^{2} + 2abi - {b}^{2} = 6 + 8i$

We then have this system of equations:

${a}^{2} - {b}^{2} = 6$

$2ab = 8$

Solving this system:

$ab = 4$

$b = \frac{4}{a}$

${a}^{2} - {( \frac{4}{a}) }^{2} = 6$

${a}^{2} - \frac{16}{ {a}^{2} } = 6$

${a}^{4} - 16 = 6{a}^{2}$

${a}^{4} - 6 {a}^{2} - 16 = 0$

$( {a}^{2} - 8)( {a}^{2} + 2) = 0$

${a}^{2} = 8$

$a = 2 \sqrt{2}$

$b = \frac{4}{2 \sqrt{2} } = \sqrt{2}$

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2 years ago

Read 2 more answers

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Ksivusya [100]

The answer is A. true, since the order of operations goes as follows:

Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

One way I was taught to remember it was by creating a saying out of the first letters(PEMDAS=Please Excuse My Dear Aunt Sally).

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3 years ago

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MrRissso [65]

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3 years ago