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Blababa [14]
3 years ago
9

Write an equation in point-slope form of the line through point J(4,1) with slope -4.

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
4 0
Point slope form
y - y1 = m(x - x1)

Plug in the given
slope = -4
Point ( 4, 1)

y - 1 = -4(x - 4)
y - 1 = -4x +16
add 1 to both sides
y = -4x + 17

Hope this helps!
ladessa [460]3 years ago
4 0

Answer:

The point-slope form of the line is y - 1 = -4(x - 4)

Step-by-step explanation:

In order to find the equation of the line, you start with the base form of point-slope form.

y - y1 = m(x - x1)

Now, input the slope in for m and the point in for (x1, y1).

y - 1 = -4(x - 4)

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F(x)=cos(x). Find the x-intercepts of f(x) on [0, 2).
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The x-intercepts of the function where the function is given as y(x) = cos(x) are π/2 and 3π/2

<h3>What is the x-intercept of the function?</h3>

The x-intercept of the function is the point or points where the graph of the function crosses the x-axis i.e. the point where the function equals 0

<h3>How to find the x-intercepts of the function?</h3>

The function is given as

f(x) = cos(x)

And the interval is given as

[0, 2)

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The above equation can be solved graphically

See attachment for the graph of the function f(x) = cos(x)

In the interval [0, 2), the graph crosses the x-axis at points x = π/2 and 3π/2

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3 0
1 year ago
The problem is in the pictures, please show step by step how to do it. Thanks! :)
Rama09 [41]

Answer:

-4,-5/2

Step-by-step explanation:

2x^2+3x-20 =0

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Either,

x+4=0

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Or,

2x-5=0

2x=5

x=5/2

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