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Nuetrik [128]
4 years ago
9

All cars have a speedometer and an odometer. Which one measures a rate of change? What are the two variables in this rate of cha

nge?
Mathematics
1 answer:
ryzh [129]4 years ago
3 0

Answer:

Step-by-step explanation:

The speedometer measures the rate of change of distance with respect to time.

The odometer displays the total distance traveled since it was set to 0.00.

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If the blue radius below is perpendicular to the green chord and the segment BC is 7.6 units long, what is the length of the cho
galina1969 [7]

Answer:

The correct answer is A. 15.2 units

Step-by-step explanation:

The segment AB is congruent to the segment BC  eg AB≅BC Why?

We can prove it with the triangle congruent theorem, postulate side-side-angle

We are watching triangle ΔABO and triangle ΔCBO, they are congruent

first element side OB=OB - common side

second element side OA=OC=r - radius of the circle

third element angle ∡ABO≅∡CBO=90°

According to the postulate side-side-angle we can conclude that triangles

ΔABO≅ΔCBO (triangles are congruent)

If they are congruent all of their elements are also congruent and therefore also

side AB=BC  => AB+BC=AC,  which is chord  => 7.6+7.6=15.2 units

AC= 15.2 units ( chord )

Good luck!!!


6 0
3 years ago
Multiplying binomials<br> Determine the product<br> (x-3) (x-8)
MrMuchimi
X^2-24 is the answer
4 0
3 years ago
Read 2 more answers
The original price of a computer game is $45. The price is marked down by $18. What percent of the original price is the markdow
natali 33 [55]

Answer:

60%

Step-by-step explanation:

To know the discount, we must know how much that $ 18 represents of the original price, as follows:

18/45 = 0.4

That is, $ 18 is 40% of $ 45

Therefore, to calculate the discount we must subtract what represents 45%, that is, 100%

100% - 40% = 60%

In other words, the discount is 60%

6 0
4 years ago
Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers
Mars2501 [29]

Answer:

a) Let \frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

b)

Let \frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.

Observe that

\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

c)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}

d)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.

Observe that

\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}

3 0
3 years ago
How to prove that IC is parallel with AB?
Karo-lina-s [1.5K]
There is something wrong with drawing. IC intercepts with AB at A.
7 0
3 years ago
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