Answer:
The possible number of goats is 6 and the possible number of chicken is 24
Step-by-step explanation:
Let
chicken=c
Goat=g
the number of chickens could be four times the number of goats
c=4g
Total number of animals=30
c+g=30
Recall, c=4g
So,
c+g=30
4g+g=30
5g=30
Divide both sides by 5
5g/5=30/5
g=6
Recall,
c+g=30
c+6=30
c=30-6
=24
c=24
The possible number of goats is 6 and the possible number of chicken is 24 making a total of 30 animals
B) 7/10
It is B because there are 7 out of 10 possibilities that you would get a number greater than 7 or an odd number.
Answer:
C. 7 hours
Step-by-step explanation:
Let the time for the trip out be represented by t. Then the time for the return trip is t-1. The distance was the same for both trips, so we have ...
distance = speed × time
300t = 350(t -1)
300t = 350t -350 . . . . eliminate parentheses
350 = 50t . . . . . . . . . . add 350-300t
7 = t . . . . . . divide by 50
The trip out took 7 hours.
The answer to 6 2/3 divide by 9 2/3 should equal to 20/29.
Assume Charles charges $7*3=$21 if he babysits for 2,5 hours (that is 2 and a half hours).
That is we are not considering Charles babysitting exactly 1, 2, 3 or 4 hours, but also in between times.
then we can write the following piecewise function to describe the situation:
f is a function from (0, 4] to {$7, $14, $21, $28}