Please help ASAP!! will give brainliest :)

Dvinal [7]

Answer:

q = 3 units

Step-by-step explanation:

$In\: \triangle GFH \: and\; \triangle GJI\\\angle GFH \cong \angle GJI..(each\: 90\degree)\\\angle FGH \cong\angle JGH..(common\: angles)\\\therefore \triangle GFH \sim \triangle GJI..(by \: AA\: postulate)\\\\\therefore \frac{GF}{GJ}=\frac{HF}{IJ}..(By\: c.s.s.t.)\\\\\therefore \frac{4}{8}= \frac{q}{6}\\\\\therefore \frac{1}{2}= \frac{q}{6}\\\\q =\frac{6}{2}\\q= 3 \: units$

7 0

2 years ago

What is the range of the function graphed below?

Akimi4 [234]

Answer:

C.

$- \infty < y < \infty$

6 0

3 years ago

Whitch three capital letters have rotational symmetry but do not have line symmetry

deff fn [24]

First you want to figure out what exactly it is you are looking for. We are looking for "capital letters that have rotational symmetry but do not have line symmetry"

So:
1. Must have rotational symmetry.
This means that if we rotate the capital letter 180 deg, either clockwise or counterclockwise, it will still look the same

2. Must not have line symmetry.
If an object has line symmetry, it means that if you draw a line down the middle (in any way), it will be symmetrical on both sides. We need capital letters that do not fit that condition.

Now we look at all capital letters.
We find that H, I, N,O, S, X, and Z are all rotationally symmetrical. Think about it. If you rotate them, they still look the same.

But, we have to make sure they do not have line symmetry. If we draw a line right down the middle of H, I, O and X (**note, the have multiple lines of symmetry), they are symmetrical on both sides of the line.

Now we are left with N, S, and Z

4 0

3 years ago

Read 2 more answers

List the sequence of transformations. ()=−2(−3)^4+1

SVEN [57.7K]

We have the function:

()=−2(−3)^4+1

We need to go from this equation to the parent function x^4. To do that, we first do a vertical translation of 1 unit below. That is:

Vertical translation: f(x) - 1

= −2(−3)^4

Now, we make a horizontal shift of 3 units to the left, replacing x by x + 3:

f(x + 3) + 1 = −2()^4

Horizontal shift: f(x + 3) - 1

= −2x^4

We can make a horizontal expansion if we multiply this function by 1/2:

Horizontal expansion: ( f(x + 3) - 1 ) / 2

= -x^4

Finally, we make a reflection around the x-axis by multiplying this result by -1:

x-axis reflection: -( f(x + 3) - 1 ) / 2

= x^4

8 0

6 months ago

• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando

antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$Z = \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}$

$Z = \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}$

$Z = \frac{- 0.09}{ 0.048989 }$

$Z = - 1.84$

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0

3 years ago

Please help ASAP!! will give brainliest :)​

Please help ASAP!! will give brainliest :)