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3 years ago

When i am solving for the sides of a right triangle when will i use trigonometric functions

Mathematics

1 answer:

AnnZ [28]3 years ago

6 0

Answer:

The ratios of the sides of a right triangle are called trigonometric ratios. We need to use trigonometric functions to find them when we don't have any angle other than 90 degree shown.

Three common trigonometric ratios are the sine (sin), cosine (cos), and tangent (tan). These are defined for acute angle.

However when we have one angle given with the 90 degree we can deduct without trigonometry but we would use all angles to find the hypotenuse or all angles to find the side of a right angle.

Alternatively, we cna do this with one given angle but if we have one, we might as well work out the other one without trigonometry and do a division with Sin = 25 (sin 35) sin 90 / sin 55

is one example when given the base 25ft that would find the hypotenuse or the length of elevation for buildings looking down or zip-wire questions.

Step-by-step explanation:

| \

l \

4cm| \ 5cm

| \

B | - - - - \ C

3cm

Suppose we wanted to find sin( A) in△ABC

(The height of the wall in elevation questions would be used above the base shown 3cm at the start) Sin = 3 (sin 35)° sin 90° / sin 55° to find the height side (4).

Sine is defined as the ratio of the opposite to the hypotenuse

sin(A) = hypotenuse = AB/BC = 3/5

/ opposite

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Vitek1552 [10]

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<h3>What is the volume of the sphere?</h3>

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Volume of a sphere = 4/3πr³

Where:

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To learn more about the volume of a sphere, please check: brainly.com/question/13705125

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2 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

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Given:

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$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

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Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

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3 years ago

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HACTEHA [7]

Answer:

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Step-by-step explanation:

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