Step-by-step explanation:
Since, K is the midpoint of JL.
I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.
Because, you can't just have 1 to 4, as some of the numbers are less than 1. Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.
For the second question:
I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.
So, the answers are: A) and D).
Answer:
(a+b)^2+(a-b)^2=2(a^2+b^2)
expanding:
a² + 2ab + b² + a² -2ab + b² = 2a² + 2b²
2a² + 2b² = 2a² + 2b²
<span>180
n is the number of games. In this case it is 15. Enter this number into the function:
b(n) = 12n = 12(15) = 180.
Simply put, 12 balls are needed for each game.
15 x 12 = 180</span>
