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KiRa [710]
4 years ago
10

The sequence is recursive. Find the value of the next term in the sequence.

Mathematics
1 answer:
timurjin [86]4 years ago
5 0
For this problem, given that this is a recursive series. The next term in the sequence is:

16

The reason is because the distance between two consecutive terms is always equal to two



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2.
Iteru [2.4K]

answer:

x = 0.80

y = 1.50

step-by-step explanation:

x = cost of tacos

y = cost of burritos

both equations:

3x + 2y = 5.40

2x + 1y = 3.10

             ^

turn this | into this |

                             v

               y = 3.10 - 2x

then add it to the equation :

3x + 2 [ 3.10 - 2x ] = 5.40

3x + 6.2 - 4x = 5.40

-1x = - 0.8

x= 0.80

then add x = 0.80 to the equations to get :

3 [ 0.80 ] + 2y = 5.40

2.4 + 2y = 5.40

2y = 3

y = 1.5

5 0
3 years ago
What is the solution to −2(2x−6)+4x≤−8x+4(−2x−5) ?
olga_2 [115]

Answer:

x<_-2 ( x is less than or equal to -2)

Step-by-step explanation:

First remove opposites and collect like terms so it will be -4x+12+4x<_-8x-8x-20.

Then move them to be 12<_-16x-20.

Move -16x to the left and the 12 to the right to combine it with -20 to become -32.

You are now left with 16x<_-32.

Divide both sides by 16 to get x<_-2.

Hope this helped :) btw <_ is less than or equal to i just dont know how to put the sign on top of the underscore :/

6 0
3 years ago
5(y + 2/5) = -13<br><br> Solve for y<br><br> Show or explain your method
Natalija [7]
Step 1. Multiply 5 by y and you get 5y
Step 2. Multiply 5 by .4(2/5)
Step 3. Your equations will look like 5y+2=-13
Step 4. Subtract 2 from its self and -13
Step 5. Your equation will be 5y=-15
Step 6. Divide 5 from both sides
Step 7. Your answer is y=-3
8 0
3 years ago
Read 2 more answers
Help asap marking as BRAINLIST ace only
Soloha48 [4]

Answer:

O: The circle's name is "O"

Step-by-step explanation:

A circle is ALWAYS named for the center point. The point in the center of this circle is "O" so the circle is named "O"

8 0
3 years ago
Let A and B be subsets of a universal set U and suppose n(U)=400, n(A)=135, n(B)=80, and n(A n B)=60. Find the number of element
Alexxandr [17]
Use A' for A complement, etc. and n = intersection &cap;.
n(A' n B')
=n(A u B)'   by the de Morgan's law
=nU-n(nA+nB-n(AnB))     n(A u B) = nA + nB - n(AnB)  and nX'=nU-nX
=400-(135+80-60)
=400-155
=245
5 0
4 years ago
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