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KiRa [710]
3 years ago
10

The sequence is recursive. Find the value of the next term in the sequence.

Mathematics
1 answer:
timurjin [86]3 years ago
5 0
For this problem, given that this is a recursive series. The next term in the sequence is:

16

The reason is because the distance between two consecutive terms is always equal to two



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Given the graph below, find the slope. <br><br> A. -3/2<br> B.3/2<br> C -2/3<br> D. 2/3
Irina18 [472]
The answer is or the slope is D 2/3
8 0
3 years ago
What is the fifth term in the geometric sequence described by this explicit formula y=40×(-2)^(n-1)​
cupoosta [38]

Answer:

The fifth term is 620

Step-by-step explanation:

y=40×(-2)^(n-1)​

The 5th terms means n=5

y = 40 * (-2) ^ (5-1)

  = 40 * (-2) ^4

  = 40 * (16)

  = 640

5 0
3 years ago
EASY POINTSSSS AND BRAINLIEST
DiKsa [7]

Answer:

1. 3:1

2. also 3:1

Step-by-step explanation:

ratio has nothing to do with measurements

6 0
3 years ago
Read 2 more answers
What is the shape of the graph of the function?<br> g(x)= 3/2 (2/3) ^x
Andrew [12]

Answer:

Please check the attached graph.

From the graph, it is clear that option B is the correct option.

Step-by-step explanation:

Given the function

g\left(x\right)=\:\frac{3}{2}\:\left(\frac{2}{3}\right)^x

Determining the y-intercept

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

so

substituting x = 0 in the fuction

y=\:\frac{3}{2}\:\left(\frac{2}{3}\right)^x

y=\:\frac{3}{2}\:\left(\frac{2}{3}\right)^0

Apply rule:  a^0=1,\:a\ne \:0

y=1\cdot \frac{3}{2}

y=\frac{3}{2}

y = 1.5

Therefore, the point representing the y-intercept is:

  • (0, 1.5)

Determining the x-intercept

We know that the value of the x-intercept can be determined by setting y = 0, and determining the corresponding value of x.

so

substituting y = 0 in the function

0=\frac{3}{2}\left(\frac{2}{3}\right)^x

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

\left(\frac{2}{3}\right)^x=0

We know that a^{f\left(x\right)} can not be zero or negative for x ∈ R

Thus, NONE represents the x-intercept.

Please check the attached graph.

From the graph, it is clear that option B is the correct option.

5 0
3 years ago
Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0
BartSMP [9]

The power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}

We can write g(x) as,

\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\

We know that, \frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n} if |x| < 1

and \frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n  if |\frac{x}{6}| < 1

\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\     if |x| < 1 and  if |\frac{x}{6}| < 1

\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n) if |x| < 1

Therefore, the power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0
2 years ago
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