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nekit [7.7K]
3 years ago
6

How many ways can a dozen books be placed on four distinguishable shelves if no two books are the same, and the positions of the

books on the shelves matter (ie. if Book 1 is to the left of Book 2, that is different from if Book 1 is to the right of Book 2)
Mathematics
1 answer:
Jet001 [13]3 years ago
5 0

Answer:

217945728000 ways

Step-by-step explanation:

Given

Books = 12 --- 1 dozen

Shelf = 4

The given condition implies that;

Book\ 1  = 4 ---- any of the 4 shelves

Book\ 2  = 5 --- any of the 4 shelves and either ways of book 1

Book\ 3  = 6  --- any of the 4 shelves and either ways of book 1 and 2

-----------------------

----------------

----------

<h2>Book\ 12 = 15</h2><h2></h2>

So, the number of ways is:

Ways = 4 * 5 * 6 * 7 * 8 * 9 * 10 * 11 * 12 * 13 * 14 * 15

Ways = 217945728000

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It takes 4 weeks at minimum for each pair to hug at least once if they sit in random order.

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As per the given information,

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Determining the Number of Weeks

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2 years ago
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