Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
See Explanation
Step-by-step explanation:
Given:
See Attachment
Required
Complete the table
From the question, we understand that:
So:
When square meters = 1
When square meters = 10
Assume any value of square meter for the third row;
Say: square meters = 20
When square meters = a
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Answer:
Hey there!
This is because the theoretical probability is different from the experimental probability. The theoretical probability is what is expected, but the experimental probability is what actually happens.
Hope this helps :)
Answer:
56
Step-by-step explanation:
you have to find the LCM of 7 AND 8.
which is 56
Answer:
1. A
2. C
Step-by-step explanation:
FOR QUESTON 1: r/2 + ( 7/8 - s)
1/2 + ( 7/8 - 1/2) = 7/8 ( A )
FOR QUESTION 2: 2/3 ( n - 6) p
2/3 ( 10 - 6) 1/2 = 4/3 ( C )
