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yan [13]
4 years ago
6

The current in a wire is 0.72 A, calculate the charge that passes through the wire in 7 mins

Physics
1 answer:
yKpoI14uk [10]4 years ago
4 0
We know, I = Q / t
Here, I = 0.72 A
t = 7 min = 7*60 = 420 s

Substitute their values, 
0.72 = Q / 420
Q = 420 * 0.72
Q = 302.4 C

In short, Your Answer would be 302.4 Coulombs

Hope this helps!
You might be interested in
Please could you help me. A race car travels along a straight length of track at 65 m/s. The race car and driver have a
leva [86]

Answer:

1.23×10⁶ J

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 65 m/s

Mass (m) = 580 Kg

Kinetic energy (KE) =?

The kinetic energy can be obtained by using the following formula :

KE = ½mv²

Where:

KE => is the kinetic energy.

m => is the mass

v => is the velocity

With the above formula, we can obtain the kinetic energy as follow:

Velocity (v) = 65 m/s

Mass (m) = 580 Kg

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 580 × 65²

KE= 290 × 4225

KE = 1.23×10⁶ J

Thus, the kinetic energy is 1.23×10⁶ J

8 0
3 years ago
Which set of equipment would be most useful to determine the density of a liquid?
NemiM [27]
Triple beam balance/scale to find mass, and graduated cylinder to find volume
3 0
4 years ago
An amplifier produces a sound wave with a power of 1.00 μW (micro-Watt). If it is a point source and radiates uniformly in all d
gtnhenbr [62]

Answer:

(a) I=8.84*10^{-9}W/m^{2}

(b) \beta =39.46dB

Explanation:

Given data

The source is 1.00 μW

The point is 3m away from the point source

For Part (a)

The intensity at a certain distance from a point source that emits sound wave is given as:

I=\frac{P_{s} }{4\pi r^{2} }\\I=\frac{1*10^{-6}W  }{4\pi (3m)^{2} } \\I=8.84*10^{-9}W/m^{2}

For Part (b)

The Sound level is given by

β=(10dB)×log(I/I₀)

Where

I₀=1×10⁻¹²W/m²

Substitute the given values to find Sound level

So

\beta =(10dB)log(\frac{8.84*10^{-9}W/m^{2}  }{1*10^{-12}W/m^{2}} )\\\beta =39.46dB

4 0
3 years ago
A child with a mass of 20 kg sits at a distance of 2 m from the pivot point of a seesaw. where should a 16-kg child sit to balan
Maksim231197 [3]
In the above problem, we need to find mass of the second child, so that the Center of Mass remains at the origin( pivot).

CM= m1r1+m2r2/m1+m2
0= 20*-2+16*r2/20+16
r2= 40/16
r2= +2.5 m

4 0
3 years ago
Which sets of data show a wave with the shortest wavelength? A. Speed=100 million m/s and frequency = 50 million Hz. B. Speed=15
SashulF [63]
The answer is <span>A. Speed=100 million m/s and frequency = 50 million Hz.</span>

Let's calculate for each choice the wavelength using the equation:
v = f × λ   ⇒ λ = v ÷ f<span>

where:
v - the speed,
f - the frequency,
</span>λ - the wavelength.

A:
v = 100 000 000 m/s
f = 50 000 000 Hz = 50 000 000 1/s (Since f = 1/T, so units are Hz = 1/s)
⇒ λ = 100 000 000 ÷ 50 000 000 = 2 m

B:
v = 150 000 000 m/s
f = 1 500 Hz = 1 500 1/s
⇒ λ = 150 000 000 m/s ÷ 1 500 = 100 000 m

B:
v = 300 000 000 m/s
f = 100 Hz = 100 1/s
⇒ λ = 300 000 000 m/s ÷ 100 = 3 000 000 m

According to these calculations, the shortest wavelength is needed for choice A.
3 0
3 years ago
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