Answer:
(a) 45 micro coulomb
(b) 6 micro Coulomb
Explanation:
C = 3 micro Farad = 3 x 10^-6 Farad
V = 15 V
(a) q = C x V
where, q be the charge.
q = 3 x 10^-6 x 15 = 45 x 10^-6 C = 45 micro coulomb
(b)
V = 2 V, C = 3 micro Farad = 3 x 10^-6 Farad
q = C x V
where, q be the charge.
q = 3 x 10^-6 x 2 = 6 x 10^-6 C = 6 micro coulomb
Bulbs c and b would still be screwed in if they were in to begin with and bulbs A, D, and E. would be unscrewed
The distance between the two balls at the given force is 0.7 m.
The given parameters;
- <em>mass of each ball, m = 0.8 kg</em>
- <em>gravitational force between the balls from sample problem C, F = 8.92 x 10⁻¹¹ N</em>
The distance between the balls is calculated by applying Coulomb's law as shown below;
![F = \frac{Gm^2}{r^2} \\\\r^2 = \frac{Gm^2}{F} \\\\r = \sqrt{\frac{Gm^2}{F} } \\\\r = \sqrt{\frac{(6.67\times 10^{-11}) \times (0.8)^2}{8.92 \times 10^{-11}} } \\\\r = 0.7 \ m](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7BGm%5E2%7D%7Br%5E2%7D%20%5C%5C%5C%5Cr%5E2%20%3D%20%5Cfrac%7BGm%5E2%7D%7BF%7D%20%5C%5C%5C%5Cr%20%3D%20%5Csqrt%7B%5Cfrac%7BGm%5E2%7D%7BF%7D%20%7D%20%5C%5C%5C%5Cr%20%3D%20%5Csqrt%7B%5Cfrac%7B%286.67%5Ctimes%2010%5E%7B-11%7D%29%20%5Ctimes%20%280.8%29%5E2%7D%7B8.92%20%5Ctimes%2010%5E%7B-11%7D%7D%20%7D%20%5C%5C%5C%5Cr%20%3D%200.7%20%5C%20m)
Thus, the distance between the two balls is 0.7 m.
Learn more about Coulomb's law here: brainly.com/question/14270204
Answer:
3. It has the same net charge as 11 protons.
Explanation:
An electrically neutral object contains the same number of protons and electrons. Therefore, if 11 electrons are removed from it, there will be 11 more protons compared to the number of electrons in the object. Thus, the object It has the same net charge as 11 protons.
Answer:
The normal force will be "122.8 N".
Explanation:
The given values are:
Weight,
W = 100 N
Force,
F = 40 N
Angle,
θ = 35.0°
As we know,
⇒ ![N=W+FSin \theta](https://tex.z-dn.net/?f=N%3DW%2BFSin%20%5Ctheta)
On substituting the given values, we get
⇒ ![= 100N+40N \ Sin \theta](https://tex.z-dn.net/?f=%3D%20100N%2B40N%20%5C%20Sin%20%5Ctheta)
⇒ ![=100N+22.8](https://tex.z-dn.net/?f=%3D100N%2B22.8)
⇒ ![=122.8 \ N](https://tex.z-dn.net/?f=%3D122.8%20%5C%20N)