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Y_Kistochka [10]
1 year ago
13

Why is soil considered a non-renewable resource?

Physics
2 answers:
Sever21 [200]1 year ago
7 0

Answer:D

Explanation: It is considered non renewable, it takes hundreds of years to renovate and because our life span as humans is very limited we don’t get to see how it regenerates.

svetlana [45]1 year ago
6 0
D.soil can only be formed by natural processes…
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Can Hotspots can be found at the edges of tectonic plates?
PolarNik [594]

Answer:

No.

Explanation:

Hot spots don't appear at the barriers of tectonic plates, instead, they originate at hot centres known as mantle plumes. Mantle plumes exist below the tectonic plates and may develop a string of volcanoes on the Earths surface.

6 0
2 years ago
The 49-g arrow is launched so that it hits and embeds in a 1.45 kg block. The block hangs from strings. After the arrow joins th
Dimas [21]

Answer:

the initial speed of the arrow before joining the block is 89.85 m/s

Explanation:

Given;

mass of the arrow, m₁ = 49 g = 0.049 kg

mass of block, m₂ = 1.45 kg

height reached by the arrow and the block, h = 0.44 m

The gravitational potential energy of the block and arrow system;

P.E = mgh

P.E = (1.45 + 0.049) x 9.8 x 0.44

P.E = 6.464 J

The final velocity of the system after collision is calculated as;

K.E = ¹/₂mv²

6.464 = ¹/₂(1.45 + 0.049)v²

6.464 = 0.7495v²

v² = 6.464 / 0.7495

v² = 8.6244

v = √8.6244

v = 2.937 m/s

Apply principle of conservation of linear momentum to determine the initial speed of the arrow;

P_{initial} = P_{final}\\\\mv_{arrow} + mv_{block} = (m_1 + m_2)V\\\\0.049(v) + 1.45(0) = (0.049 + 1.45)2.937\\\\0.049v = 4.4026\\\\v = \frac{4.4026}{0.049} \\\\v = 89.85 \ m/s

Therefore, the initial speed of the arrow before joining the block is 89.85 m/s

4 0
2 years ago
How can I connect projectile motion into inclines. plsss give me ideas
Alenkasestr [34]

Answer:

Explanation:

Initial launch angle, θ

Initial velocity, u.

Time of flight, T.

Acceleration, a.

Horizontal velocity, vx.

Vertical velocity, vy.

Displacement, d.

Maximum height, H.

4 0
3 years ago
A machine part has the shape of a solid uniform sphere of mass 225 g and diameter 3.00 cm. It is spinning about a frictionless a
maw [93]

Answer: a) angular acceleration(alpha)=-14.8rad/s^2

b) time taken (t) = 1.52s

Explanation:

What we are given

Mass of the solid sphere m =225g = 0.225kg

Diameter D = 3.00cm = 0.0300m

Radius = D/2 = 0.01500m

Frictional Force = 0.0200N

a) to determine the angular acceleration, we first calculate the torque, then moment of inertia, before the angular acceleration.

Torque = -fr

= - (0.0200)(0.01500)

=-3.00X10^-4Nm

Moment of inertia I

= 2/5mr^2

=2/5(0.225)(0.01500)^2

=2.025X10^-5kgm^2

Angular acceleration (alpha)= torque/moment of inertia (I)

= -3.00X10^-4Nm/2.025X10^-5kgm^2

=-14.8rad/s^2

b) time taken (∆t) = w/alpha

w= -22.5rad/s

Angular acceleration (alpha) = -14.8rad/s^2

∆t = -22.5/-14.8

= -1.52s

6 0
3 years ago
During a game the same batter swings at a ball thrown by the pitcher and hits a line drive. Just before the ball is hit it is tr
sergeinik [125]

Answer:

The total work on the ball is 36.25 Joules

Explanation:

There is an important principle on classical mechanics that is the work-energy principle it states that the total work on an object is equal the change on its kinetic energy, mathematically expressed as:

W_{net}=\Delta K = K_f -K_i (1)

With W net the total work, Kf the final kinetic energy and Ki the initial kinetic energy. We're going to use this principle to calculate the total work on the baseball by the force exerted by the bat.

Kinetic energy is the energy related with the movement of an object and every classical object with velocity has some kinetic energy, it is defined as:

K=\frac{mv^2}{2}

With m the mass of the object and v its velocity, knowing this we can use on:

W_{net}= \frac{mv_f^2 -mv_i^2}{2}=\frac{m(v_f^2 -v_i^2)}{2}

In our case vf is the velocity just after the hit and vi the velocity just before the hit. For an average baseball its mass is 145g that is 0.145 kg, then

W_{net}=\frac{0.145*(30.0^2 -20.0^2)}{2}

W_{net}=36.25 J

8 0
3 years ago
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