Please mates, look at the image and the questions that I will writeand tell me the correct answer with explanation, I really nee
d them for today!!!!!!!!!!
Q1. Which one of the following is the equation of the line passing through the origin and having slope 4?
A. Y= -0.4x
B. Y= 4x
C. Y= -4x
D. Y= 0.4x
Q2. What is the solution set of 9x-4<13x-7? (domain,xez)
A. (1,2,3)
B. (1,2,3......)
C. (0,1,2,3,...)
D. (0,1,2,3)
Q3. If three fourth of a number is one tenths, what is the number?
A. 2/15
B. 3/40
C. 17/20
D. 7/20
Q4. A pairs of fair die is tossed. What is probability of not setting a sum 13?
A. 0
B. 1
C. 2
D. 0.5
Q5. If the cost price is greater than the selling price, then which one is formed?
A. Profit
B. % Profit
C. S.P- C.P is positive
D. Loss
Q6. Which one of the following is true about the row data given below 4,7,8,4,6 and 1?
A. The median is 6
B. The mean is equal to the median
C. The mode is equal to the median
D. The range is 8
Q1. Which one of the following is the equation of the line passing through the origin and having slope 4?
A. Y= -0.4x
B. Y= 4x
C. Y= -4x
D. Y= 0.4x
Q2. What is the solution set of 9x-4<13x-7? (domain,xez)
A. (1,2,3)
B. (1,2,3......)
C. (0,1,2,3,...)
D. (0,1,2,3)
Q3. If three fourth of a number is one tenths, what is the number?
A. 2/15
B. 3/40
C. 17/20
D. 7/20
Q4. A pairs of fair die is tossed. What is probability of not setting a sum 13?
A. 0
B. 1
C. 2
D. 0.5
Q5. If the cost price is greater than the selling price, then which one is formed?
A. Profit
B. % Profit
C. S.P- C.P is positive
D. Loss
Q6. Which one of the following is true about the row data given below 4,7,8,4,6 and 1?
A. The median is 6
B. The mean is equal to the median
C. The mode is equal to the median
D. The range is 8
1 answer:
You might be interested in
Please see the pic, I'd solved in it.
Given:
$7/child
$10/adult
Total people = 700
Total money = $6,400
First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people
1. a+c = 700
2. 10a+7c = 6,400
Then, rearrange the equation to solve for a variable.
c = 700-a
Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9
a = 633
= # of adults attended
700-633 = c = 66 
= # of children attended
$7/child
$10/adult
Total people = 700
Total money = $6,400
First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people
1. a+c = 700
2. 10a+7c = 6,400
Then, rearrange the equation to solve for a variable.
c = 700-a
Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9
a = 633
700-633