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otez555 [7]
3 years ago
6

Benito wants to buy a car. He is considering two different models. Model A is 6 7/8 feet wide. Model B is 75 inches wide. Expres

s the width of each car using feet using a decimal. Which car is bigger?
Mathematics
1 answer:
marishachu [46]3 years ago
7 0
Model A is the bigger car.

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9. The formula V = wh is the volume formula for a rectangular prism. Find the length
Lelu [443]
Answer c 10cm
good luck
4 0
3 years ago
Find the equation of the line that passes through point (6, 1) with the x-intercept of 2.
34kurt

<u>Answer:</u>

○ y = \frac{1}{4}x - \frac{1}{2}

<u>Step-by-step explanation:</u>

To find the equation of the line, let's first consider the points whose coordinates we have been given:

• (6, 1)

• (2, 0).

The point (2, 0) is what is called the x-intercept, which is the point where the line crosses the x-axis. This means that at this point, the y-coordinate of the line is 0.

Next, let's calculate the slope (gradient) of the line using the formula:

m = \frac{y_2 - y_1}{x_2 - x_1}

where:

m = gradient,

(x_2, y_2) and (x_1, x_2) = points on the line.

Using the formula:

m = \frac{1 - 0}{6 - 2}

⇒ m =\bf \frac{1}{4}

Finally, now that we have two points on the line as well as the line's slope, we can use the following formula to find the equation of the line:

\boxed{y - y_1 = m(x - x_1)}

You can use any of the points on the line as y_1 and x_1.

Using (2, 0):

y - 0 = \frac{1}{4}( x - 2)

⇒ y = \frac{1}{4}x - \frac{1}{2}

Therefore the equation of the line is y = \frac{1}{4}x - \frac{1}{2}.

Learn more about point-slope form at:

brainly.com/question/15143525

6 0
1 year ago
HELP!!!!!! Which point approximates V3?<br> A) A<br> B) B<br> C C<br> D D
Igoryamba

Answer:

c

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6 0
3 years ago
The graph compares the weights in pounds of 100 dogs and cats that are brought in to a veterinarian's office.
GenaCL600 [577]
In case of dogs the value 10 is the minimum value. So all the values lie above 10. In total there were 100 dogs.
So for dogs, we can say number of dogs above the value of 10 pound are 100.

In case of Cats, 10 lies at the position of median. Median is the central value and 50% values lie above the median value. So number of cats with weight above 10 pound is 50.

Thus, we can conclude that there were 50 more dogs than the cats with weight over 10 pounds. So option C gives the correct answer.
8 0
3 years ago
Read 2 more answers
Simplify: -3(m – 2) – 7m <br><br> A. -10m + 6 <br> B. -4m + 6 <br> C. 4m – 6 <br> D. 10m + 6
Masja [62]
The correct answer is A
4 0
3 years ago
Read 2 more answers
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