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3 years ago

Domain and Range only for 4 5 and 6

Mathematics

2 answers:

natima [27]3 years ago

8 0

For a Function→y=f(x),

Domain is the set of all x values for which y is defined.

Range of a function is defined as, set of all possible values of y, for which x is defined.

For the function given in Question 4

⇒For every value of x lying in the interval from (-∞,∞), there are value of y which will lie in the interval (-∞,∞).

Domain of the function=(-∞,∞)=R

Range of the Function =(-∞,∞)=R

⇒For a Linear function in Question 5

Domain as well as Range =(-∞,∞)=R

⇒For the Function given in Question 6

Domain =[0,4]

Range=[-2,2]

yKpoI14uk [10]3 years ago

6 0

Answer:

4. Domain is all reals and range is 2, -∞

5. Domain and Range is both all reals

6. Domain is 0<x<4 and Range is -3<y<3

Step-by-step explanation:

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Which numbers are solutions

Tom [10]

Answer:

6 and 3

Step-by-step explanation:

x^2 - 9x + 18 = 0

(x-6)•(x-3)=0

if x-6 = 0 then x = 6

and if x-3= 0 then x = 3

3 0

3 years ago

Read 2 more answers

What ere the coordinates of the point on the directed line segment from (-1,7) to (7,7) that partitions the segment into a ratio

djverab [1.8K]

Answer:

$(\frac{37}{11},\frac{77}{11} )$

Step-by-step explanation:

Given two points are (-1,7) and (7,7).

We are told to find a point which is in between them at a ratio of 6:5.

Formula for calculating a point at distance of ratio m:n is given by

$(\frac{mx2+nx1}{m+n} ,\frac{my2+ny1}{m+n} )$

where $(x1,y1),(x2,y2)$ are the inital and final points.

$(x1,y1)=(-1,7)\\\\(x2,y2)=(7,7)$

also m:n=6:5 ,

by substituting all the values we get,

$(\frac{6*7+5*-1}{11} ,\frac{6*7+5*7}{11} )$

$(\frac{37}{11},\frac{77}{11} )$

5 0

3 years ago

0.18(y-9)+0.06y=0.04y-0.9

Ksju [112]

Simplify both sides then isolate the variable and it gives you y=3.6

7 0

3 years ago

You are taking hang-gliding lessons. The cost of the first lesson is one and a half times the cost of each additional lesson. Yo

kow [346]

So, givens: total lesson cost of $260, total lessons taken are 6, and the first lesson costs 1.5 (or 3/2) as much as the additional lessons.

First thing to do is to figure out how many additional lessons are in that, which are 5.

Then you can make a 1 variable equation with the information you have. I’m using x as my variable.

260= 3/2x + 5x

Combine like terms.

260 = 13/2x

Divide both sides by 13/2 (treat it as a fraction, and if your calculator cannot make fractions, then decimal might help for this. 13/2=6.5)

X=40

8 0

2 years ago

A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the

hoa [83]

Answer:

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone ≈ 12.57 m²

Step-by-step explanation:

The given parameters are;

The height of the cone = 5 m

The base radius of the cone = 2 m

The angle which the A $\hat O$ C = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone

The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°

∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

8 0

3 years ago