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mihalych1998 [28]
3 years ago
5

Is this a function or no?

Mathematics
2 answers:
spayn [35]3 years ago
8 0

Answer:

No

Step-by-step explanation:

The numbers can not go into each other with nothing coming out.

Andrei [34K]3 years ago
5 0

Answer:

Nope

Step-by-step explanation:

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What happens to the volume of a cylinder when the height is doubled
sveticcg [70]

Answer:

If the radius of a cylinder is doubled and height is halved, the volume will be doubled. If the radius of a cylinder is doubled and height is halved, the volume will be doubled.

Step-by-step explanation:

I just search on g o o g l e

7 0
3 years ago
The original price of a blender is $18.00. If the blender is discounted 25%, what is the new price?
Ivanshal [37]

Answer:

$4.50

Step-by-step explanation:

Please give brainliest!!

6 0
3 years ago
In 1980 (before the era of in-vitro fertilization), there were 3,612,258 births in the United States (according to the U.S. Cens
scoray [572]

Answer:

There was a 1.93% probability of having multiples (twins or more) in 1980.

Step-by-step explanation:

There were 3,612,258 births in the US in 1980.

Of those,

68339 + 1337 = 69676 were multiplies.

So

What was the probability of having multiples (twins or more) in 1980?

P = \frac{69676}{3612258} = 0.0193

There was a 1.93% probability of having multiples (twins or more) in 1980.

8 0
3 years ago
A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of
ddd [48]

There are

\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}

ways of pairing up any 2 members from the pool of 2n contestants. Note that

(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)

so that

\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}

4 0
2 years ago
Daniela invested a total of $50,000, some in a certificate of deposit (CD) and the remainder in bonds. The amount invested in bo
LekaFEV [45]

Answer:

The amount invested in bonds = 35,000

The amount invested in CD = 15,000.

Step-by-step explanation:

The total amount that Daniela invested is $50,000, this means if we call the amount invested in bonds b, and the amount invested in CD d, then we have:

b+d=50,000 this says the total amount Daniela invested is $50,000.

And since the amount invested in bonds b is $5,000 more than twice the amount Daniela put into the CD, we have:

b=5,000+2d.

Thus, we have two equations and two unknowns b and d:

(1). b+d=50,000

(2). b=5,000+2d,

and we solve this system by substituting b from the second equation into the first:

b+d=50,000\\5,000+2d+d=50,000\\3d=45,000\\\\\boxed{d=15,000}

or, the amount invested in CD is $15,000.

With the value of d in hand, we now solve for b from equation(2):

b=5,000+2d\\b=5000+2(15,000)\\\boxed{b=35,000}

or, the amount invested in bonds is $35,000.

4 0
3 years ago
Read 2 more answers
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