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sineoko [7]
3 years ago
8

Duc has a trapezoid shaped section of his yard fenced off for his pets. The lengths of the parallel sides of the trapezoid are 8

ft and 14 ft. The height of the trapezoid section is 4 ft.
What is the area of the trapezoid section of the yard?

Enter your answer in the box.

ft²
Mathematics
2 answers:
noname [10]3 years ago
5 0
Area of the trapezoid = 1/2(B+b)h
where
B= length of the longer side of the trapezoid which is equal to 14 ft
b= shorter shorter side of the trapezoid  which equal 8 ft
h = height of the trapezoid which is equal to 4 ft
Area of the trapezoid = 1/2 (14+8)4
Area of the trapezoid yard fence of Duc is 44ft^2
Andrew [12]3 years ago
4 0

The answer is 44 ft my dudes

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There are 157 college students interviewed about their work schedules. 85 of them work during the day. 43 of them work nightshif
stepan [7]

Step-by-step explanation:

No of students work during day shift = 85

No of students work during night shift = 43

No of students working both shift = 28

So first we will divide 28 by 2 = 14

Then it means there were 14 students working in day shift and 14 students working in night shift

Total number of students work during day shift = 85 + 14 = 99

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3 years ago
Which diagram represents a cylinder with a base area equal to 50 square meters?
juin [17]

Answer:

it's the third option

Step-by-step explanation:

8 0
2 years ago
3x+4(x-8)-14 evaluate for x=11
djverab [1.8K]

Answer:

For X = 11, the expression is equal to 31

Step-by-step explanation:

Hello

For X = 11 you only have to replaced the value into the expression, so:

3(11) + 4(11-8) - 14

33 + 4(3) - 14

33 + 12 - 14

31

Best regards

4 0
3 years ago
Read 2 more answers
The point P(5,1) lies on the curve y=5x. If Q is the point (x,5x), find the slope of the secant line PQ for the following values
sveta [45]

Answer:

5

Step-by-step explanation:

We have been given that the point P(1,5) lies on the curve y=5x. Q is the point (x,5x). We are asked to find the slope of the secant line PQ for x=5.1.

Let us find y-coordinate corresponding to x=5.1 for point P as:

y=5(5.1)=25.5

Now, we will use slope formula to find required slope.

m=\frac{y_2-y_1}{x_2-x_1}  

Let point (1,5)=(x_1,y_1) and point (5.1,25.5)=(x_2,y_2).

Using these points in slope formula, we will get:

m_{PQ}=\frac{25.5-5}{5.1-1}=\frac{20.5}{4.1}=5

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8 0
4 years ago
Alright, second try. 15 Points to whoever can solve with a half-decent explanation.
sesenic [268]

Answer:

29 cans

Step-by-step explanation:

To solve this problem we must use Heron's formula; A = \sqrt{S(S-a)(S-b)(S-c)}

S = 1/2 the perimeter of the given triangle

a, b, c = the measurements of the three given sides

The first step to solving this question is first finding the perimeter.

P = 65m + 74m + 67m

P = 206m

Now that we have our perimeter, we must divide P by 2 to get S.

S = 206/2

S = 103

Now we plug our numbers into Heron's formula.

A = \sqrt{S(S-a)(S-b)(S-c)}

A = \sqrt{103(103-65)(103-67)(103-74)}

A = \sqrt{103(38)(36)(29)}

A = \sqrt{103(39672)}

A = \sqrt{4086216}

Find the square root of this number.

A ≈ 2021.43909134... m²

If a can of paint covers 70 square meters, then you will need to figure out how many cans you need. This can be done by dividing the overall area of the triangle by the area that a single can of paint can cover.

\frac{2021.43909134...}{70} = 28.8777013049...

We know we can't buy 28.87... of a can (people simply do not sell parts of cans or half-full containers... unless its a bag of lays chips and their 80% air nonsense...) so we must round up to the nearest whole number.

28.87... = 29

Thus we finally have our answer: 29 cans of paint!

5 0
3 years ago
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