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spayn [35]
3 years ago
14

Solve the following eqation for x: 6(4x+5)+3=3(x+8)+3. Round to the nearest hundredth

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0
<h2>Steps</h2><h3>Equation: 6(4x + 5) + 3 = 3(x + 8) + 3</h3>

Subtract 3 from both sides

6(4x + 5) + 3 - 3 = 3( x + 8) + 3 - 3

Simplify

6( 4x + 5) = 3(x + 8)

<h3>Apply the distributive law:</h3>

6(4x + 5)

<u>a(b + c) = ab + ac</u>

a = 6, b = 4x, c = 5

= 6 x 4x + 6 x 5

<h3>Simplify</h3>

6 x 4x + 6 x 5

Multiply the numbers: <u>6 x 4 = 24</u>

= 24x + 6 x 5

Multiply the numbers: <u>6 x 5 = 30</u>

= 24x + 30

<h3>Apply the distributive law:</h3>

3(x + 8)

<u>a(b + c) = ab + ac</u>

a = 3, b = x, c = 8

= 3x + 3 x 8

Multiply the numbers: <u>3 x 8 = 24</u>

= 3x + 24

24x + 30 = 3x + 24

Subtract 30 from both sides

24x + 30 - 30 = 3x + 24 -30

Simplify

24x = 3x - 6

Subtract 3x from both sides

24x - 3x = 3x - 6 - 3x

Simplify

21x = -6

Divide both sides by 21

21x/21 = -6/21

Note: Simplify -6/21 to get the value for x.

Answer in fraction: x = -2/7

Answer in decimal rounded to the nearest hundredth: x = -0.29

I know this seems complicated; that's why I did it step by step.

<u />

netineya [11]3 years ago
7 0

24x + 33 = 3x + 27

21x + 33 = 27

21x = -6

X = -.29

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Answer:

The true statements are:

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C. Lower and upper quartiles are needed to find the interquartile range

E. The data values should be listed in order before trying to find the interquartile range

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Steps to find the interquartile range:

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B. Interquartile ranges are not significantly impacted by outliers ⇒ True <em>(because it does not depends on the smallest and largest data)</em>

<em />

C. Lower and upper quartiles are needed to find the interquartile range ⇒ True <em>(because IQR = Q3 - Q2)</em>

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E. The data values should be listed in order before trying to find the interquartile range  ⇒ True <em>(because we can find the interquartial range by finding the values of the upper and lower quartiles)</em>

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